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4 years ago

How is the graph of the parent quadratic function transformed to produce the graph of y=-(2x+6)? +3?

Mathematics

2 answers:

Schach [20]4 years ago

7 0

Answer:

B on ed

Step-by-step explanation:

got D wrong on ed so it is B

Aleonysh [2.5K]4 years ago

5 0

Answer:

Step-by-step explanation:

You might be interested in

About 13% of the population of a large country is nervous around strangersnervous around strangers. If two people are randomly

Molodets [167]

Answer:

1.69% probability both are nervous around strangers.

24.31% probability at least one is nervous around strangers.

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they are nervous around strangers, or they are not. The people are chosen randomly, which means that the probability of a person being nervous around strangers is independent from other people. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

About 13% of the population of a large country is nervous around strangers.

This means that $p = 0.13$ .

Two people are randomly selected

This means that $n = 2$ .

What is the probability both are nervous around strangers?

This is $P(X = 2)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{2,2}.(0.13)^{2}.(0.87)^{0} = 0.0169$

1.69% probability both are nervous around strangers.

What is the probability at least one is nervous around strangersnervous around strangers?

This is $P(X \geq 1)$

$P(X \geq 1) = P(X = 1) + P(X = 2)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{2,1}.(0.13)^{1}.(0.87)^{1} = 0.2262$

$P(X = 2) = C_{2,2}.(0.13)^{2}.(0.87)^{0} = 0.0169$

$P(X \geq 1) = P(X = 1) + P(X = 2) = 0.2262 + 0.0169 = 0.2431$

24.31% probability at least one is nervous around strangers.

3 0

3 years ago

Can someone please help!

artcher [175]

Hello,

First of all the point-slope equation will have this form : $y=ax+b$

$b = y-intercept = 3\\\\a=\dfrac{\Delta y}{\Delta x}=\dfrac{-3-5}{2}=-4\\\\y=-4x+3$

Answer A.

Because :
$if:y+5=-4(x-2)\\\\y+5=-4x+8\\y=-4x+8-5\\y=-4x+3$

7 0

3 years ago

Dose anyone know the answer??

r-ruslan [8.4K]

In any function y = f(x) , set of all possible values of x define the domain of f(x), in the graph The curve in terms of x-axis(in 1st & 3rd quadrant) goes from -4 to -2(doesnt include -2).

So domain = [-4, -2)

Similarly, in 2nd and 4th quadrant, for x-axis

It goes from 2 to 5 (doesnt include 2 & 5)

So domain = (2, 5)

Hence,

Domain of the f(x) is [-4, -2) U (2, 5).

Range tells the possible values of y, for this function it goes from -5 to +3(doesnt include 3).

Range is [-5, 3)

4 0

3 years ago

Given that a randomly chosen flight arrives on time, what is the probability that it arrives in Philadelphia (PHL)?

olga55 [171]

Using concepts of probability, it is found that there is a 4.7% probability that it arrives in Philadelphia (PHL).

<h3>What is a probability?</h3>

A <em>probability </em>is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.

Over a large number of trials, a percentage can also represent the probability of single event.

In this question, researching the problem on the internet, we have that over a large number of flights, of those which arrived on time, 4.7% of them were in Philadelphia, hence:

There is a 4.7% probability that it arrives in Philadelphia (PHL).

You can learn more about probabilities at brainly.com/question/15536019

3 0

2 years ago

In order to solve the following system of equations we add :

vlabodo [156]

False, you want to subtract in order to get rid of the 2x in both equations

5 0

3 years ago