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trasher [3.6K]
3 years ago
14

Joseph has hypothesized that sound travels in waves. If he were following the scientific method, what should he do next?

Chemistry
2 answers:
ss7ja [257]3 years ago
7 0
B. Test the hypothesis
Mandarinka [93]3 years ago
6 0

Answer:  B.  Test the hypothesis.

Explanation:  As already mentioned that Joseph has already hyptheiszed that sound travel in waves. According to the scientific method, he must now test his hypothesis by performing calculations and experiments.

As experiments in the foundation of any scientific investigation, thus he can prove his hypothesis only by performing experiments.

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O. How many protons, neutrons and electrons are in Neodymium - 144 (Nd-144)?
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Diagram of the nuclear composition, electron configuration, chemical data, and valence orbitals of an atom of neodymium-144 (atomic number: 60), an isotope of this element. The nucleus consists of 60 protons (red) and 84 neutrons (orange). 60 electrons (white) successively occupy available electron shells (rings).
8 0
3 years ago
Based on the formulas, select the compounds that are covalent.
Sedbober [7]
S2F10, FE3N2, S7O2, NaCO3,  Al2O3, PC13, and CO2. Hope this helps
3 0
3 years ago
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How many liters of oxygen gas are there in 45.0g O, at 0 degrees C and 1 atm of pressure? make sure to round to the correct numb
ZanzabumX [31]

Answer:

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Explanation:

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3 0
2 years ago
The Ka for formic acid (HCO2H) is 1.8 × 10-4. What is the pH of a 0.35 M aqueous solution of sodium formate (NaHCO2)?
anzhelika [568]

Answer:

9.36

Explanation:

Sodium formate is the conjugate base of formic acid.

Also,

K_a\times K_b=K_w

K_b for sodium formate is K_b=\frac {K_w}{K_a}

Given that:

K_a of formic acid = 1.8\times 10^{-4}

And, K_w=10^{-14}

So,

K_b=\frac {10^{-14}}{1.8\times 10^{-4}}

K_b=5.5556\times 10^{-11}

Concentration = 0.35 M

HCOONa    ⇒     Na⁺ +    HCOO⁻

Consider the ICE take for the formate  ion as:

                                   HCOO⁻ + H₂O   ⇄   HCOOH + OH⁻

At t=0                              0.35                            -              -

At t =equilibrium           (0.35-x)                          x           x            

The expression for dissociation constant of sodium formate is:

K_{b}=\frac {[OH^-][HCOOH]}{[HCOO^-]}

5.5556\times 10^{-11}=\frac {x^2}{0.35-x}

Solving for x, we get:

x = 0.44×10⁻⁵  M

pOH = -log[OH⁻] = -log(0.44×10⁻⁵) = 4.64

pH + pOH = 14

So,

<u>pH = 14 - 4.64 = 9.36</u>

5 0
3 years ago
The nucleus of an atom ok K-42 contains
horsena [70]
Number of proton K=19

so, 42 - 19 =23

then the answer in 19 protons and 23 neutrons
3 0
3 years ago
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