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Advocard [28]
3 years ago
8

Will zinc and sodium carbonate react?

Chemistry
1 answer:
AleksAgata [21]3 years ago
3 0
A reaction will not occur since sodium is higher than zinc in the electrochemical series of metal. 

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What is the pH of 1.00 L of a buffer that is 0.110 M nitrous acid (HNO2) and 0.200 M NaNO2? (pKa of HNO2 = 3.40)
Andrei [34K]

Answer:

pH = 3.65    

Explanation:

given data

pKa of HNO2 = 3.40

nitrous acid (HNO2) = 0.110 M

NaNO2 = 0.200 M

to find out

What is the pH

solution

we get here ph for acidic buffer  that is express as

pH = pKa + log(salt÷acid)      ........................1

put here value and we get

pH = 3.40 + log(0.200÷0.110)

pH = 3.65    

4 0
3 years ago
A solution that contains a large amount of salt and a small amount of water is said to be a _______ solution. A. diffused B. uns
Pachacha [2.7K]

Answer:

D. Concentrated

Explanation:

5 0
3 years ago
Read 2 more answers
In a fluorine atom, on which energy level are the valence electrons found?
aivan3 [116]

Answer:

second energy level

Explanation:

Valence electrons are those electrons which are present in outer most orbital of the atom.

This can be easily found through the electronic configuration of atom.

Electronic configuration of F:

F₉ = 1s² 2s² 2p⁵

We can see that the valence electrons are present in second energy level of F atom.

There are seven valence electrons of fluorine.

It is called halogens.

Halogens are very reactive these elements can not be found free in nature. Their boiling points also increases down the group which changes their physical states. i.e fluorine is gas while iodine is solid.

Fluorine:

1. it is yellow in color.

2. it is flammable gas.

3. it is highly corrosive.

4. fluorine has pungent smell.

5. its reactions with all other elements are very vigorous except neon, oxygen, krypton and helium.  

6 0
3 years ago
The process that changes the identity and number of protons in a nucleus is
Pavlova-9 [17]
<span>The process that changes the identity and number of protons in a nucleus is fusion, transmutation, and fission.</span>
3 0
3 years ago
What happens to the rate if the concentration of 1-iodopropane remains the same and the concentration of sodium hydroxide is dou
Sphinxa [80]

Answer:

The rate of reaction is doubled

Explanation:

The reaction between 1-iodopropane and sodium hydroxide is an SN2 reaction. This reaction takes place by a concerted mechanism and the hydroxide ion is the nucleophile.

In an SN reaction, the reaction is second order because the rate of reaction depends both on the concentration of the alkylhalide and that of the nucleophile. Hence, when the concentration of 1-iodopropane (the alkyl halide) is held constant and the concentration of hydroxide ion (the nucleophile) is doubled, the rate of reaction is doubled since;

Rate =k [1-iodopropane] [OH^-]

4 0
3 years ago
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