Answer:
D.141 g
Explanation:
Given that:-
Mass of ethylene = 45.0 g
Molar mass of ethylene = 28.05 g/mol
The formula for the calculation of moles is shown below:
Thus,
According to the reaction below:-
1 mole of ethylene produces 2 moles of carbon dioxide
So,
1.60 mole of ethylene produces 2*1.60 moles of carbon dioxide
Moles of carbon dioxide = 3.2 mol
Molar mass of carbon dioxide = 44.01 g/mol
Mass = Moles*Molar mass = 3.2 mol x 44.01 g/mol = 141 g
<u>D.141 g of carbon dioxide will be produced</u>
Answer: 25.89g of O2 (g)
Explanation:
We begin by finding the molar mass of compounds of interest in the given equation. 2 KClO3 ⟶ 2 KCl + 3 O 2
1 mole of KCLO3 = 39 .10 + 35.5 + (3x16) = 122.55g, 2Moles would be 2 x 122.5 = 245.1g
1 mole Oxygen gas = 32g, 3 moles would be, 3 x 32= 96g
According to the equation;
245.1g of KCLO3 produces 96g of O2 (g)
If 1g of KCLO3 produces 96÷245.1 of O2 (g) from heating.
66.1g of KCLO3 would produce; 96÷245.1 x 66.1 = 25.89g of O2 (g) from heating.
Answer:positive
Explanation: because there are more protons than electrons in the ion
Answer:
Alphabet C :NADH is oxidized,CO2 is reduced