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Alecsey [184]
3 years ago
13

PLEASE HELP!! What is the percentage by mass of solution formed by dissolving 27.0 grams of HCl in 102.0 grams of water? 26.5% 2

0.9% 18.2% 16.7%
Chemistry
1 answer:
densk [106]3 years ago
7 0

The answer is 20.9%; you have to divide the solute by the total number of grams; thus divide 27/129 and get B)20.9%

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38 points!! >:D
Sav [38]

Answer: which*

Explanation:

8 0
3 years ago
Read 2 more answers
25.0 g sample of compound A is mixed with a 40.0 g sample of compound B. a chemical reaction occurs. Once the reaction is comple
artcher [175]

Answer:

Explanation:

Mass of compound A  = 25g

Mass of compound B = 40g

Mass of final mixture = 55g

What happens to the missing mass?

According to the law of conservation of mass, in chemical reaction, matter is transformed from one form to another but cannot be created nor destroyed.

We expect the final mass of the mixture and that of the reacting compounds to be the same but the opposite is the case.

There is a mass loss which typifies most chemical reaction.

The reason for this is that some of the masses must have been lost by the production of gaseous species which are unaccounted for.

The missing mass:

  Total mass expected  = mass of A + mass of B = 25 + 40 = 65g

Missing mass = expected mass - mass of final mixture = 65 - 55 = 10g

4 0
3 years ago
What mass of Sodium Chloride is required to make 100.0 mL of 3.0 M solution?
Julli [10]

Answer:

17.55 g of NaCl

Explanation:

The following data were obtained from the question:

Molarity = 3 M

Volume = 100.0 mL

Mass of NaCl =..?

Next, we shall convert 100.0 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

100 mL = 100/1000

100 mL = 0.1 L

Therefore, 100 mL is equivalent to 0.1 L.

Next, we shall determine the number of mole NaCl in the solution. This can be obtained as follow:

Molarity = 3 M

Volume = 0.1 L

Mole of NaCl =?

Molarity = mole /Volume

3 = mole of NaCl /0.1

Cross multiply

Mole of NaCl = 3 × 0.1

Mole of NaCl = 0.3 mole

Finally, we determine the mass of NaCl required to prepare the solution as follow:

Mole of NaCl = 0.3 mole

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Mass of NaCl =?

Mole = mass /Molar mass

0.3 = mass of NaCl /58.5

Cross multiply

Mass of NaCl = 0.3 × 58.5

Mass of NaCl = 17.55 g

Therefore, 17.55 g of NaCl is needed to prepare the solution.

5 0
3 years ago
19. This type of bond involves the bonding of two ions of opposite charges
hammer [34]

Answer:

Covalent bond is a type of bond involves the bonding of two ions of opposite charges.

<h3><u>PLEASE</u><u> MARK</u><u> ME</u><u> BRAINLIEST</u><u>.</u></h3>
7 0
3 years ago
Can you help me with this with a solution
LuckyWell [14K]

The complete table is inserted.

A table is given,

Formulas used:

pH=  -log(H⁺)

pOH=  -log(OH⁻)

pH+ pOH=14

Calculations:

For A: (H⁺)=2×10⁻⁸M

Using the pH formula:

pH=  -log(H⁺)=-log(2×10⁻⁸)=7.69

pOH=14 - 7.69=6.3

Calculating OH concentration,

pOH=  -log(OH⁻)

6.3= -log(OH⁻)

(OH⁻)=5.011×10⁻⁷M

Hence, the nature of A is basic.

Similarily,

For B,

(OH⁻)=1×10⁻⁷

Using the pH formula:

pOH=  -log(OH⁻)= -log(1×10⁻⁷)=7

pH=14-7=7

Calculating H concentration,

pH=  -log(H⁺)

7= -log(H⁺)

(H⁺)=1×10⁻⁷M

Hence, the nature of B is neutral.

Similarily,

For C,

pH=12.3

Using the pH formula:

pOH=14-12.3=1.7

Calculating H concentration,

pH=  -log(H⁺)

12.3= -log(H⁺)

(H⁺)=5.011×10⁻¹³M

Calculating OH concentration,

pOH=  -log(OH⁻)

1.7= -log(OH⁻)

(OH⁻)=1.99×10⁻²M

Hence, the nature of C is Basic.

Similarily,

For D,

pOH=6.8

Using the pH formula:

pH=14-6.8=7.2

Calculating H concentration,

pH=  -log(H⁺)

7.2= -log(H⁺)

(H⁺)=6.309×10⁻⁸M

Calculating OH concentration,

pOH=  -log(OH⁻)

6.8= -log(OH⁻)

(OH⁻)=1.58×10⁻⁷M

Hence, the nature of D is basic.

Learn more about the acid and bases here:

brainly.com/question/16189013

#SPJ10

3 0
2 years ago
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