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1 year ago

HELP NEED THIS DONE BEFORE 9:45!!!!!!!!!!!!!!!! WILL GIVE 100 POINTS AND BRAILIEST IF DONE BEFORE 9:45!!!!!!!!!!!!!

Chemistry

2 answers:

ehidna [41]1 year ago

7 0

Answer:

1.) 742.57 m/s

2.) 132

3.) 4.375 hours

4.) 1080

5.) 81.6 km per hour

6.) 20 min = 1,200 secs1000 / 1200

Explanation:

Your Welcome!

sveticcg [70]1 year ago

7 0

Answer:

1.) 742.57 m/s

2.) 132 m

3.) 4.375 hours

4.) 1080 m

5.) 81.6 km per hour

6.) 20 min = 1,200 secs1000 / 1200

Explanation:

**Brainliest would be appreciated**

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Mass of ammonium chloride formed = 26.7455 g

(b)

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Explanation:

(a)

For the first reaction:-

$NH_3_{(g)}+HCl_{(g)}\rightarrow NH_4Cl_{(s)}$

The mole ratio of the reactants = 1 : 1

0.5 moles of ammonia react with 0.5 moles of hydrochloric gas to give 0.5 moles of ammonium chloride

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Molar mass of ammonium chloride = 53.491 g/mol

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(b)

For the first reaction:-

$CH_4_{(g)}+4S_{(s)}\rightarrow CS_2_{(l)}+2H_2S_{(g)}$

The mole ratio of the reactants = 1 : 4

It means

0.5 moles of methane react with 2.0 moles of sulfur to give 0.5 moles of Carbon disulfide and 1.0 moles of hydrogen sulfide gas.

But available moles of S = 0.5 moles

Limiting reagent is the one which is present in small amount. Thus, S is limiting reagent.

The formation of the product is governed by the limiting reagent. So,

4 moles of S produces 1 mole of $CS_2$

Thus,

0.5 moles of S produces $\frac{1}{4}\times 0.5$ mole of $CS_2$

Mole of $CS_2$ = 0.125 mole

Molar mass of $CS_2$ = 76.139 g/mol

Mass = Moles * Molar mass = 0.125 * 76.139 g = 9.52 g

4 moles of S produces 2 moles of $H_2S$

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0.5 moles of S produces $\frac{2}{4}\times 0.5$ mole of $H_2S$

Mole of $H_2S$ = 0.25 mole

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