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vampirchik [111]
3 years ago
10

You have the choice of logging on at one of two Internet cafés. Their posted rates are as follows: Log-On Café: $5.50 plus $0.15

for every minute online eCafé: $4.00 plus $0.20 for every minute online Which café is the best option if you plan on using the Internet for 45 minutes? What is the equation that relates the number of minutes used and the total cost, and how much money will you save?
Mathematics
1 answer:
erastovalidia [21]3 years ago
4 0
1. 5.50 + 0.15 * 45 = 12.25

2. 4 + 0.20 * 45 = 13

So the first option is slightly better, you can save 13-12.25= $0.75.
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At the grocery store, apples are one price and chocolate bars are another. mary buys three apples and one chocolate bar for $2.7
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Answer:

Step-by-step explanation:

Step 1 is to collect the information in a table format.  The attached Table1 summarizes what we know in columns 1 - 3. Columns 4 - 6 show the data we're about to calculate, so ignore them for the moment.

.I use A for the price of one apple and C for the price of 1 chocolate bar.  We know how many of each are purchased by both Mary and Bill, and the total each paid.  

The last column (6) shows the price for each, which comes from the derivation presented below.

We can set the information in columns 1 - 3 into equations:

Mary:  3A+1C = 2.70   [This states that Mary bought 3 apples at a price of A for each apple, and 1 chocolate bar at a price of C per bar.]

Bill:      1A + 4C = 6.40  [In the same fashion, this summarizes how Bill parted with his $6.40]

---

Now let's rearrange either equation to solve for C.  I'll use Mary's equation:

3A+1C = 2.70

1C = 2.70 - 3A

This tells us that the price of 1 chocolate bar is $2.70 minus the cost of 3 apples.  Interesting, but we need the price of a chocolate bar to determine an exact amount.

----

Now take Bill's equation and substitute the value we just derived for the price of a chocolate bar <u>C</u> = (2.70-3A).

1A + 4<u>C</u> = 6.40

1A + 4(2.70 - 3A) = 6.40

1A + 10.80 - 12A = 6.40

-11A = -4.40

A = 0.40    This is the price for 1 apple.  This is the value in the last column (6) of attached Table1.

---

Now we can use the value of $0.40 in either equation to find the price of a chocolate bar.  I'll use the rearranged equation we developed for Mary:

1C = 2.70 - 3A

1C = 2.70 - 3(0.40)   [A = 0.40 from the above work]

1C = 2.70 - 1.20

1C = 1.50

The price of 1 chocolate bar is $1.50.  Pricey, and bad for health.  But very tasty.

Columns 4 and 5 are the total costs for the apples and bars bought by each, and their sums add up to the amounts we were given at the start of the problem.  So our prices must be correct.

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Chantelle has signed up for hockey. Her parents set a limit of 40$ for costs for the season. It costs 25$ to sign up plus 0.75$
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X=(40-25)/.75

X= 15/.75

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