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kifflom [539]
3 years ago
10

What does the principal quantum number determine? Check all that apply. Check all that apply. the possible number of electorns o

n particular orbital the energy of the electron on the outer shell the shape of the orbital the overall size of an orbital the orientation of the orbital the overall size of an atom the energy of an orbital
Chemistry
1 answer:
vladimir2022 [97]3 years ago
8 0

Answer:

ii) the energy of the electron on the outer shell

iv) the overall size of an orbital

Explanation:

There are four quantum numbers to define the position and energy level of an electron in an atom

a) Principal : The principal quantum number (n) is to know the energy of an electron in an atom and its possible distance from the nucleus.

b) Azimuthal: It refers to the shape of the subshell or orbital of the electron and thus the angular distribution.

c) Magnetic: It refers to the number of orbits and their orientation in the subshell.

d) spin: It refers to the spin of the electron.

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He orbital period of an object is 2 × 107 s and its total radius is 4 × 1010 m
gtnhenbr [62]

Answer:

The answer is 12,560  

Explanation:

The orbital period is the time a given cosmic question takes to finish one circle around another protest and applies in space science as a rule to planets or space rocks circling the Sun, moons circling planets, exoplanets circling different stars, or double stars. Mercury, for instance, has an orbital time of 88 days while it takes Jupiter around 11.86 years. The time of the Earth's circle is generally thought to be 365 days as timetables appear.

6 0
3 years ago
Read 2 more answers
Vitellium (Vi) has the following composition:Vi-188: 187.9122 amu; 10.861%Vi-191: 190.9047 amu; 12.428%Vi-193: 192.8938 amu; 76.
yKpoI14uk [10]
10.861% / 100 = 0.10861

12.428 % / 100 = 0.12428

(0.10861 * 187.9122) + (0.12428 * 190.9407) <span>+ (0.76711 x 192.8938)</span>

= 192.1100 amu .

hope this helps!

7 0
3 years ago
An ionized helium atom has a mass of 6.6 × 10-27 kg and a speed of 5.3 × 105 m/s. It moves perpendicular to a 0.78-T magnetic fi
arsen [322]

Explanation:

In a magnetic field, the radius of the charged particle is as follows.

             r = \frac{mv}{qB}

where,   m = mass,      v = velocity

              q = charge,    B = magnetic field

Therefore, q will be calculated as follows.

         q = \frac{mv}{rB}

            = \frac{6.6 \times 10^{-27} \times 5.3 \times 10^{5}}{0.014 m \times 0.78 T}

            = \frac{34.98 \times 10^{-22}}{0.01092}

            = 3.2 \times 10^{-19} \times \frac{1.0 e}{1.6 \times 10^{-19}C}

            = +2e

Thus, we can conclude that the charge of the ionized atom is +2e.

5 0
3 years ago
In a car crash, large accelerations of the head can lead to severe injuries or even death. A driver can probably survive an acce
Alexxandr [17]

Answer:

Velocity, u = 14.7 m/s

Explanation:

It is given that, a driver can probably survive an acceleration of 50 g that lasts for less than 30 ms, but in a crash with a 50 g acceleration lasting longer than 30 ms, a driver is unlikely to survive.

Let v is the highest speed that the car could have had such that the driver survived. Using a = -50 g and t = 30 ms

Using first equation of kinematics as :

v=u+at

In case of crash the final speed of the driver is, v = 0

0=u+at

-u=at

-u=-50\times 9.8\times 30\times 10^{-3}

u = 14.7 m/s

So, the highest speed that the car could have had such that the driver survived is 14.7 m/s. Hence, this is the required solution.

8 0
3 years ago
A major component of gasoline is octane when octane is burned in air it chemically reacts with oxygen to produce carbon dioxide
yan [13]

gasoline is the chemical that is coming out of the air

7 0
3 years ago
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