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raketka [301]
3 years ago
12

He orbital period of an object is 2 × 107 s and its total radius is 4 × 1010 m

Chemistry
2 answers:
gtnhenbr [62]3 years ago
6 0

Answer:

The answer is 12,560  

Explanation:

The orbital period is the time a given cosmic question takes to finish one circle around another protest and applies in space science as a rule to planets or space rocks circling the Sun, moons circling planets, exoplanets circling different stars, or double stars. Mercury, for instance, has an orbital time of 88 days while it takes Jupiter around 11.86 years. The time of the Earth's circle is generally thought to be 365 days as timetables appear.

alukav5142 [94]3 years ago
4 0

Answer:

12,560 m/s.

Explanation:

The question is missing:

<em>What is the tangential speed of the satellite?</em>

Tangential speed (Vt) is defined as the length of the arc (s) covered per unit of time (t), that is:

Vt = s/t

The period specifies the time the satellite takes to complete the orbital. The whole circumference has an arc length of 2*π*radius. Replacing into the equation:

Vt = 2*π*4*10^10 m /(2*10^7 s)

Vt = 12,560 m/s

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What happens when
jolli1 [7]

Answer:

a i think but idk

Explanation:

3 0
3 years ago
A 150.0mL sample of an aqueous solution at 25C contains 15.2mg of an unknown nonelectrolyte compound. If the solution has an osm
Nookie1986 [14]

Answer:

MM = 225.11 g/mol

Explanation:

In this case, let's analyze the data.

We have a 15.2 mg of an unknown electrolyte in 150 mL of solution. The osmotic pressure is 8.44 Torr, and we want the molecular mass of the unknown.

The osmotic pressure can be calculated using the following expression:

π = CRT   (1)    

π: osmotic pressure (8.44 Torr * 1 atm / 760 Torr = 0.011 atm)

C: Concentration of the unknown in the solution

R: universal constant of gases (0.082 L atm / K mol)

T: temperature in Kelvin (25 + 273 = 298 K)

From this expression, we can either solve for C, and then use another expression to calculate the molecular mass, or we can just replace the expressions in the above formula, to get the direct molecular mass. In this case, we'll follow the second method.

Concentration or molarity of a substance can be calculated using:

C = moles / V  (2)

And moles can be calculated using this expression:

moles = m / MM   (3)

Replacing (3) in (2), and then in (1) we have:

C = m / MM * V

π = m * RT / MM * V   (4)

and now, we can solve for MM:

MM = mRT / π V  (5)

Now, we just need to replace the given data into the above expression to get the value of the molecular mass:

MM = (15.2 / 1000) * 0.082 * 298 / 0.011 * 0.150

<h2>MM = 225.11 g/mol</h2>

Hope this helps

3 0
3 years ago
How many grams of H,O are needed to produce 13 g of NaOH? 2 Na,O2 + 2 H20-4 NaOH + O2
fgiga [73]

Answer:

This is a typical stoichiometry question.To answer this question you want to get a relationship between

N

a

2

O and NaOH.

So you can get a relationship between the moles of

N

a

2

O

and moles of NaOH by the concept of stoichiometry.

N

a

2

O +

H

2

O ----------------> 2 NaOH.

According to above balanced equation we can have the stoichiometry relationship between

N

a

2

O and NaOH. as 1:2

It means 1 moles of

N

a

2

O is required to react with one mol of

H

2

O to produce 2 moles of NaOH.

in terms of mass 1 mole of

N

a

2

O has mass 62 g on reaction with water produces 2 moles of NaOH or 80 g of NaOH.

62 g of

N

a

2

O produces 80 g of NaOH.

1g of NaOH is produced from 62/80 g of

N

a

2

O

1.6 x

10

2

g of NaOH will require 62 x 1.6 x

10

2

g / 80 of

N

a

2

O

124g of

N

a

2

O.

Explanation:

3 0
3 years ago
Metallic bonding occurs between atoms of<br> 1.)sulfur<br> 2.)copper<br> 3.)fluorine<br> 4.)carbon
adelina 88 [10]

Answer:

copper

Explanation:

metallic bonds occur among the metal atoms where iconic bonds join metal and nonmetals metallic bonding joins a bolt of metal atoms a sheet of aluminum foil and a copper wire are both place where you can see metallic bonding in action the Sea of electrons that is free to flow about the crystal of positive metal ions

3 0
2 years ago
A 0.69-g sample of lime (CaO) is dissolved in enough water to make 1535 mL of solution. Calculate the pH of of the solution.
Marizza181 [45]

Answer:

pH = 12.2

Explanation:

Given data:

Mass of lime = 0.69 g

Volume = 1535 mL (1535 / 1000 = 1.535 L)

pH of solution = ?

Solution:

First of all we will determine the molarity.

Molarity = moles of solute / volume in litter

Number of moles = mass / molar mass

Number of moles = 0.69 g / 56.1 g/mol

Number of moles = 0.0123 mol

Molarity = moles of solute / volume in litter

Molarity = 0.0123 mol / 1.535 L

Molarity =  0.008 M

One mole of CaO neutralize two mole of OH⁻.

0.008 M×2 = 0.016 M

[OH⁻] = 0.016 M

pOH = -log [OH⁻]

pOH = [0.016]

pOH = 1.8

14 = pH +pOH

pH = 14 - pOH

pH = 14-1.8

pH = 12.2

4 0
3 years ago
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