He orbital period of an object is 2 × 107 s and its total radius is 4 × 1010 m

Chemistry

2 answers:

gtnhenbr [62]3 years ago

6 0

Answer:

The answer is 12,560

Explanation:

The orbital period is the time a given cosmic question takes to finish one circle around another protest and applies in space science as a rule to planets or space rocks circling the Sun, moons circling planets, exoplanets circling different stars, or double stars. Mercury, for instance, has an orbital time of 88 days while it takes Jupiter around 11.86 years. The time of the Earth's circle is generally thought to be 365 days as timetables appear.

alukav5142 [94]3 years ago

4 0

Answer:

12,560 m/s.

Explanation:

The question is missing:

What is the tangential speed of the satellite?

Tangential speed (Vt) is defined as the length of the arc (s) covered per unit of time (t), that is:

Vt = s/t

The period specifies the time the satellite takes to complete the orbital. The whole circumference has an arc length of 2*π*radius. Replacing into the equation:

Vt = 2*π*4*10^10 m /(2*10^7 s)

Vt = 12,560 m/s

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The pH at the equivalence point will be a. less than 7.00 b. equal to 7.00 Allohalineup of a sto quivalence point of a titration

True [87]

Answer: c. greater than 7.00

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