Can sugar and water be separated using distillation?

1. Does the bowling ball have more potential energy or kinetic energy as it sit on top of the building? Why?

Luden [163]

The bowling ball have more gravitational potential energy as it sit on top of the building

<u>Explanation:</u>

The energy that is possessed by an object due to the position of that object in the field of gravity is called Gravitational potential energy . The object that is present in the place that is very closer to the Earth's surface has a constant gravitational potential energy. When an object is at certain height there is a necessity of force for lifting that object form that height.

This is applies to the gravitational potential energy also.When two objects are placed at different heights, the object that is placed at the greater height will have more potential energy. This is because, the force necessary to take the object from greater height will be more.

6 0

3 years ago

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FeSO4 • 7H2O

Mrac [35]

Answer:

1. Percent by mass of H₂O = 45.3%

2. Percent by mass of anhydrous Salt (FeSO₄) = 54.7 %

Explanation:

Data Given

Formula of the Molecule = FeSO₄ • 7H₂O

% by mass water (H₂O) = ?

% by mass FeSO₄ = ?

________________________________________

> First of all find the atomic masses of each component in a molecule

For H₂O atomic masses are given below

H = 1 g/mol

O = 16 g/mol

> Then find the total mass of H₂O in haydrated salt

7H₂O = 7 (2x1 +1x16) g/mol

7H₂O = 7 (2+16) g/mol

7H₂O = 7 (18) g/mol

7H₂O = 126 g/mol

> find total Molar Mass of Molecule:

Molar Mass of FeSO₄ • 7H₂O = [56+ 32 + 16x4] + 7(2+16)

Molar Mass of FeSO₄ • 7H₂O = [56+ 32 + 64] + 126

Molar Mass of FeSO₄ • 7H₂O = 278

Now to find the mass by percent of H₂O

Formula used to find the mass by percent of a component

Percent composition of H₂O = mass of H₂O in Molecule / molar mass of FeSO₄ • 7H₂O x 100%

Put the values

Percent by mass of H₂O = 126 (g/mol) / 278 (g/mol) x 100%

Percent by mass of H₂O = 0.4532 x 100%

Percent by mass of H₂O = 45.3%

_______________________________________________

> First of all find the atomic masses of each component in a molecule

For anhydrus salt (FeSO₄) atomic masses are given below

Fe = 56 g/mol

S= 32 g/mol

O = 16 g/mol

> Then find the total mass of FeSO₄ in haydrated salt

FeSO₄ = (56x1 + 32 + 4x16) g/mol

FeSO₄ = ( 56 + 32 + 64) g/mol

FeSO₄ = 152 g/mol

> find total Molar Mass of Molecule:

Molar Mass of FeSO₄ • 7H₂O = [56+ 32 + 16x4] + 7(2+16)

Molar Mass of FeSO₄ • 7H₂O = [56+ 32 + 64] + 126

Molar Mass of FeSO₄ • 7H₂O = 278

Now to find the mass by percent of FeSO₄

Formula used to find the mass by percent of a component

Percent composition of FeSO₄ = mass of FeSO₄ in Molecule / molar mass of FeSO₄ • 7H₂O x 100%

Put the values

Percent by mass of FeSO₄ = 152 (g/mol) / 278 (g/mol) x 100%

Percent by mass of FeSO₄ = 0.547 x 100%

Percent by mass of FeSO₄ = 54.7 %

4 0

4 years ago

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Because of movements at the Mid-Atlantic Ridge, the Atlantic Ocean widens by about 2.5 centimeters each year. Explain which type

slamgirl [31]

Answer:

A divergent plate boundary

Explanation:

At a divergent boundary, the plates pull away from each other and generate new crust.

6 0

4 years ago

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3) If an electrical appliance has 150.0 V applied causing a current of 2.34 amps, what is the

eimsori [14]

The resistance of the appliance is 64.1 Ω.

<u>Explanation:</u>

As per the Ohm's law, which states that the electric current is in direct proportion to the voltage and is in inverse proportion to the resistance. It is given by the expression as,

V = IR

Where V is the voltage (V) = 150.0 V

I is the current (amps) = 2.34 amps

R is the resistance (ohm) or Ω = ?

Now we have to rearrange the equation to get the resistance as,

$$R = \frac{V}{I}$

Now we have to plug in the values as,

$$ R = \frac{150}{2.34}$

= 64.1 Ω

So the resistance of the appliance is 64.1 Ω.

4 0

4 years ago

Compare urban and rural land .how are each used?

Ksivusya [100]

Answer:

"Urban area is used for the buildings, industries etc, whereas the rural areas are used for cultivation, forest cover etc."

Explanation:

When we talk about the urban land they are mostly covered with buildings, industries, roads and apartments and also the municipal structures. But when we talk about the rural land it has less dense population with forest cover, agricultural lands, rangeland and also different land cover type. In the urban areas the population density is very high. Those areas that located in the outskirt of the town are the rural areas.

5 0

3 years ago