Answer: <span>b. 34.5 g/kg
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The average salinity of the ocean would be 3.45% or 35 parts per millions(ppm). That means 3.45% of the ocean water weight would be contributed by salt. Water density is 1kg/liter or 1000g/1000ml.
Then, 3.45% of it would be: 3.45% * 1000= 34.5g/kg or 34.5g/l
Answer: 0.52849 j /g °C
Explanation:
Given the following :
Mass of metal = 36g
Δ Temperature of metal = (28.4 - 99)°C = - 70.6°C
Mass of water = 70g
Δ in temperature of water = (28.4 - 24.0) = 4.4°C
Heat lost by metal = (heat gained by water + heat gained by calorimeter)
Quantity of heat(q) = mcΔT
Where; m = mass of object ; c = specific heat capacity of object
Heat lost by metal:
- (36 × c × - 70.6) = 2541.6c - - - - (1)
Heta gained by water and calorimeter :
(70 × 4.184 × 4.4) + (12.4 × 4.4) = 1288.672 + 54.56 = 1343.232 - - - - (2)
Equating (1) and (2)
2541.6c = 1343.232
c = 1343.232 / 2541.6
c = 0.52849 j /g °C
Answers:
6 goes with a.
3 goes with b.
5 goes with c.
1 goes with d.
4 goes with e.
2 goes with f.
Hope I helped, if you need explanations, please tell me :)
Answer:
25.5kg or about 56.2lbs
Explanation:
At 4°C pure water has a mass of about 1 kg/liter.
So, if there was 25.5 L of water it would be 25.5kg or about 56.2lbs.