Answer:
13 mol NO
Explanation:
Step 1: Write the balanced equation
4 NH₃(g) + 5 O₂(g) ⇒ 4 NO(g) + 6 H₂O(g)
Step 2: Establish the appropriate molar ratio
According to the balanced equation, the molar ratio of O₂ to NO is 5:4.
Step 3: Calculate the number of moles of O₂ needed to produce 16 moles of NO
We will use the previously established molar ratio.
16 mol O₂ × 4 mol NO/5 mol O₂ = 13 mol NO
Through the process of conduction, heat van be trnafered between two solids.
<u>Answer:</u> The mass of iron in the ore is 10.9 g
<u>Explanation:</u>
We are given:
Mass of iron (III) oxide = 15.6 g
We know that:
Molar mass of Iron (III) oxide = 159.69 g/mol
Molar mass of iron atom = 55.85 g/mol
As, all the iron in the ore is converted to iron (III) oxide. So, the mass of iron in iron (III) oxide will be equal to the mass of iron present in the ore.
To calculate the mass of iron in given mass of iron (III) oxide, we apply unitary method:
In 159.69 g of iron (III) oxide, mass of iron present is 
So, in 15.6 g of iron (III) oxide, mass of iron present will be = 
Hence, the mass of iron in the ore is 10.9 g