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4 years ago

Calculate the speed to which a stationary H atom would be accelerated if it absorbed a photon of wavelength 400 nm.4

Physics

1 answer:

Burka [1]4 years ago

3 0

Answer:

v=9.98*10⁻⁴m/s

Explanation:

From De Broglie's wavelength equation which is expressed as

λ=h/p

where h=planks constant, with value 6.626*10⁻³⁴J

p is the momentum expressed as p=mv

where m=mass and v=velocity. Hence we can rewrite the wavelength equation as

λ=h/mv

mass of hydrogen is given as m=1.66*10⁻²⁴kg

hence if we make the speed the subject of formula we have

V=h/mλ

V=(6.626*10⁻³⁴J)/(1.66*10⁻²⁴kg*400*10⁻⁹)

v=9.98(10⁻³⁻³⁴⁺²⁴⁺⁹)

v=9.98*10⁻⁴m/s

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2 years ago

6kg of human blood at a temperature of 65degees celcius is mixed with 4kg of human blood ata temperature of 20 degrees celcius .

Gennadij [26K]

Answer:

$T_f=47^{\circ}$

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$T_f=\frac{(m_1\cdot T_1+m_2T_2)}{(m_1+m_2)}\Rightarrow(1)$

(1) Formula basically tells us that the product of mass and temperature remains constant throughout, so the addition of two products of the two separate blood samples would be equal to the product of final temperature and the total mass of the mixture. Mathematically this means that:

$\mleft(m_1+m_2\mright)T_f=(m_1\cdot T_1)+(m_2T_2)$

Using (1) and plugging in the corresponding values, we get the answer as follows:

$\begin{gathered} T_f=\frac{(m_1\cdot T_1+m_2T_2)}{(m_1+m_2)}\Rightarrow(1) \\ m_1=6\operatorname{kg} \\ m_2=4\operatorname{kg} \\ T_1=65^{\circ} \\ T_2=20^{\circ} \\ \therefore\rightarrow \\ T_f=\frac{(6kg\cdot65^{\circ}+4\operatorname{kg}\cdot20^{\circ})}{(6kg+4\operatorname{kg})}=\frac{(390+80)}{10}=\frac{470}{10}=47^{\circ} \\ \therefore\rightarrow \\ T_f=47^{\circ} \end{gathered}$

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2 years ago

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