Ask question

Ask question

All categories

3 years ago

5

Which is the connection point between the retina and the brain?

1 answer:

Valentin [98]3 years ago

5 0

Answer:

the optic nerve

Explanation:

auditory, rods, and cones i think are to the ear.

optic means eyes, and nerves connect to the brain

You might be interested in

There is a skier at the top of a ski slope. The skier has potential energy. What gives the skier his potential energy? A. his sp

NeTakaya

Answer:C

Explanation:

Skier at the top of a ski has Potential Energy due to gravity.

Potential Energy is the Energy Possessed by an object when it attains a height concerning some zero level Position.

During the process of attaining the height, some work has to be done against gravity and this energy stored within the object after attaining some height w.r.t relative zero position.

7 0

3 years ago

Read 2 more answers

A wildlife photographer uses a moderate telephoto lens of focal length 135 mm and maximum aperture f/4.00 to photograph a bear t

labwork [276]

Answer:

<h3>(A) The width $x = 0.24 \times 10^{-3}$ m</h3><h3>(B) The new width is $1.32 \times 10^{-3}$ m</h3>

Explanation:

Given :

Focal length $f = 135 \times 10^{-3} m$

Maximum aperture $D = \frac{f}{4}$

Wavelength $\lambda = 550 \times 10^{-9}$ m

(A)

From rayleigh criterion,

$\theta = \frac{1.22 \lambda }{D}$

$\theta =\frac{ 1.22 \times 550 \times 10^{-9} }{33.75 \times 10^{-3} }$

$\theta = 1.98 \times 10^{-5}$ rad

From angle formula,

$x = R\theta$

Where $R =$ 12 m ( given in example )

$x = 12 \times 1.98 \times 10^{-5}$ m

$x = 23.76 \times 10^{-5}$

$x = 0.24 \times 10^{-3}$ m

(B)

We know that $\theta$ is proportional to the $x$ and inversely proportional to the $D$

so we write the new width, here $x$ is 5.5 times larger than above case

$x = 0.24 \times 10^{-3} \times \frac{22}{4}$

$x = 1.32 \times 10^{-3}$ m

6 0

3 years ago

A lunar lander is making its descent to moon base i. the lander descends slowly under the retro-thrust of its descent engine. th

olga_2 [115]

V = final velocity
u = initial velocity
a = acceleration
s = displacement
Take downward direction as positive.
v^2 = u^2 + 2as
v^2 = 0.8^2 + 2(1.6)(5.5)
v^2 = 18.24
v = 4.27 m/s

5 0

3 years ago

Read 2 more answers

: The truck is to be towed using two ropes. Determine the magnitudes of forces FA and FB acting on each rope in order to develop

Sholpan [36]

Answer:

Fa=774 N

Fb=346 N

Explanation:

We will solve this problem by equating forces on each axis.

On x-axis let forces in positive x-direction be positive and forces in negative x-direction be negative
On y-axis let forces in positive y-direction be positive and forces in negative y-direction be negative

While towing we know that car is mot moving in y-direction so net force in y-axis must be zero

⇒∑Fy=0

⇒ $Fa*sin(50)-Fb*sin(20)=0$

⇒ $Fa*sin(50)=Fb*sin(20)$

⇒ $Fa=2.24Fb$

Given that resultant force on car is 950N in positive x-direction

⇒∑Fx=950

⇒ $Fa*cos(20)+Fb*cos(50)=950$

⇒ $2.24*Fb*cos(20)+Fb(50)=950$

⇒ $Fb*(2.24*cos(20)+cos(50))=950$

⇒ $Fb=\frac{950}{2.24*cos(20)+cos(50)}$

⇒ $Fb=\frac{950}{2.24*0.94+0.64}$

⇒ $Fb=\frac{950}{2.75}=345.5$

⇒ $Fa=2.24*Fb$

$=2.24*345.5$

$=773.93$

Therefore approximately, Fa=774 N and Fb=346 N

5 0

3 years ago

Brainlist nd 20 points

nadezda [96]

Answer:

I'm not sure but I think it's 35-39

4 0

2 years ago

Read 2 more answers