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loris [4]
3 years ago
13

How much time does it take for a plane To fly 5000 miles if the plane travels a speed of 500 miles per hour?

Physics
2 answers:
Tasya [4]3 years ago
6 0
10 hours 500 x 2 = 1000 ...so every 2 hours = 1000 x 5 = 5000
Vitek1552 [10]3 years ago
5 0

Answer:

10 hours

Explanation:

If the plane flies at 500 miles per hour, it flies 500 miles every hour. So, to find out how many hours it will take to fly 5000, you simply do 5000/500.

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A ball with 100 J of PE is released from a height of 10 m. What will be the KE of the ball at 5
harkovskaia [24]

Answer:

The kinetic energy is: 50[J]

Explanation:

The ball is having a potential energy of 100 [J], therefore

PE = [J]

The elevation is 10 [m], and at this point the ball is having only potential energy, the kinetic energy is zero.

E_{p} =m*g*h\\where:\\g= gravity[m/s^{2} ]\\m = mass [kg]\\m= \frac{E_{p} }{g*h}\\ m= \frac{100}{9.81*10}\\\\m= 1.01[kg]\\\\

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When the elevation is 5 [m], we have a potential energy of

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8 0
3 years ago
A ball is thrown directly downward with an initial speed of 7.70 m/s, from a height of 30.2 m. After what time interval does it
KatRina [158]

Answer:

t = 1.82

Explanation:

Given

u = 7.70m/s -- initial velocity

s = 30.2m --- height

Required

Determine the time to hit the ground

This will be solved using the following motion equation.

s = ut + \frac{1}{2}gt^2

Where

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So, we have:

30.2 = 7.70t + \frac{1}{2} * 9.8 * t^2

30.2 = 7.70t + 4.9 * t^2

Subtract 30.2 from both sides

30.2 -30.2  = 7.70t + 4.9 * t^2 - 30.2

0  = 7.70t + 4.9 * t^2 - 30.2

0  = 7.70t + 4.9t^2 - 30.2

7.70t + 4.9t^2 - 30.2  = 0

4.9t^2 + 7.70t - 30.2  = 0

Solve using quadratic formula:

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a = 4.9;\ b = 7.70;\ c = -30.2

t = \frac{-7.70\±\sqrt{7.70^2 - 4*4.9*-30.2}}{2*4.9}

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t = \frac{-7.70\±25.52}{9.8}

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t = \frac{-7.70+25.52}{9.8} or t = \frac{-7.70-25.52}{9.8}

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t = \frac{17.82}{9.8}

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