5.401×10 −1 as a standard form.
2 answers:
You might be interested in
Answer: The correct option is (D) SET 4.
Step-by-step explanation: We are to select the correct set of side lengths that will form a right-angled triangle.
To form a right-angled triangle, we must have the following relation:
<em>Perpendicular² + Base² = Hypotenuse².</em>
<em>Hypotenuse is the length of the largest side; perpendicular and base are the two legs of the triangle.</em>
SET 1 : 14 cm, 5 cm, 6 cm.
We have
Therefore,
<em>Perpendicular² + Base² ≠ Hypotenuse².</em>
So, this set will not form a right-angled triangle.
SET 2 : 8 in., 12 in., 20 in.
We have
Therefore,
<em>Perpendicular² + Base² ≠ Hypotenuse².</em>
So, this set will not form a right-angled triangle.
SET 3 : 10 mm, 20 mm, 30 mm.
We have
Therefore,
<em>Perpendicular² + Base² ≠ Hypotenuse².</em>
So, this set will not form a right-angled triangle.
SET 4 : 12 ft, 16 ft, 20 ft.
We have
Therefore,
<em>Perpendicular² + Base² = Hypotenuse².</em>
So, this set will form a right-angled triangle.
Thus, the SET 4 will form a right-angles triangle.
Option (D) is correct.
Answer:
<h2>(3 + i)(4 + 2i) = 10 + 10i</h2>Step-by-step explanation:
Use FOIL: (a + b)(c + d) = ac + ad + bc + bd
and i² = -1
Answer:
The probability that a student plays either basketball or soccer is 19% or 0.19.
Step-by-step explanation:
Let A be the event that student play basketball and B be the event that student play soccer.
It is given that 6 students play on both teams.
We have to find the probability that a student plays either basketball or soccer.
Therefore the probability that a student plays either basketball or soccer is 19% or 0.19.