Answer:
cosθ = -√(35/36)
tanθ = -1/√35
Step-by-step explanation:
We know that
sin²θ + cos²θ = 1
(1/6)² + cos²θ = 1
1 - (1/6)² = cos²θ
35/36 = cos²θ
sec θ = 1/ cosθ
1/ secθ = cos θ
Because secθ < 0, 1/ secθ would also be < 0, so cos θ < 0
cosθ = -√(35/36)
tanθ = sinθ/cosθ = (1/6)/-√(35/36)
= (1/6) / -(√35/6)
= -1/√35
Using tan50=p/14=p=14*tan50
total distance betn the end of the class = 28*tan50=53.6910052ft
Answer:
7.69
Step-by-step explanation:
13.99 x 0.45 = 6.2955 or 6.3
13.99 - 6.3 = 7.69
Answer: 9 days.
Step-by-step explanation: 27 / 3
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