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amm1812
4 years ago
15

A convex spherical mirror, whose focal length has a magnitude of 21.8 cm, is to form an image 12.2 cm behind the mirror. (a) Whe

re should the object be placed?
(b) What is the magnification of the mirror?
Physics
1 answer:
Alborosie4 years ago
6 0

Explanation:

Focal length of convex mirror, f = -21.8 cm

Image distance, v = -12.2 cm

(a) Let u is the object distance. Using mirror's formula :

\dfrac{1}{v}+\dfrac{1}{u}=\dfrac{1}{f}

\dfrac{1}{u}=\dfrac{1}{f}-\dfrac{1}{v}

\dfrac{1}{u}=\dfrac{1}{-21.8}-\dfrac{1}{-12.2}

u = 27.70 cm

(b) The magnification of the mirror is the ratio of image distance to the object distance, m=\dfrac{-v}{u}

m=-\dfrac{-12.2}{27.70}

m = 0.44

Hence, this is the required solution.

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3 years ago
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insens350 [35]

Answer:

(a) 4.0334Ω

(b)parallel

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\frac{1}{3.03 } =\frac{1}{12.18}+\frac{1}{R2}

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4 years ago
You are investigating an elevator accident which happened in a tall building. An elevator in this building is attached to a stro
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Answer:

a) F = 2250 Ib

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A) The force the wall of the elevator shaft exert on the motor if the elevator starts from rest and goes up

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we first calculate the Tension using this relationship

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F = 2400 -1250 - 2400/ 4

F = 550 Ib

C ) determine design limit

Max = 2400 * 1.2 = 2880 Ib

750 + new force - 2880 = 2880 / 4

new max force ( F newmax ) = 2850 Ib

8 0
4 years ago
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