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3 years ago

Match the variables to its definition

Physics

1 answer:

MA_775_DIABLO [31]3 years ago

4 0

Answer:

See connections below

Explanation:

1 $\Rightarrow$ b

2 $\Rightarrow$ a

3 $\Rightarrow$ d

4 $\Rightarrow$ i

5 $\Rightarrow$ g

6 $\Rightarrow$ h

7 $\Rightarrow$ c

8 $\Rightarrow$ e

9 $\Rightarrow$ f

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Setler [38]

Answer:

I think 1 is d and 2 is A

Explanation:

but I may be wrong and I am so sorry if I am

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Wewaii [24]

Explanation:

Coil of wire called an winding.

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natulia [17]

Answer:

I think the first reply me if I'm wrong sorry hehe

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3 years ago

Two blocks with masses 1 and 2 are connected by a massless string that passes over a massless pulley as shown. 1 has a mass of 2

Bess [88]

Answer:

The acceleration of $M_2$ is $a = 0.7156 m/s^2$

Explanation:

From the question we are told that

The mass of first block is $M_1 = 2.25 \ kg$

The angle of inclination of first block is $\theta _1 = 43.5^o$

The coefficient of kinetic friction of the first block is $\mu_1 = 0.205$

The mass of the second block is $M_2 = 5.45 \ kg$

The angle of inclination of the second block is $\theta _2 = 32.5^o$

The coefficient of kinetic friction of the second block is $\mu _2 = 0.105$

The acceleration of $M_1 \ and\ M_2$ are same

The force acting on the mass $M_1$ is mathematically represented as

$F_1 = T - M_1gsin \theta_1 - \mu_1 M_1 g cos\theta_1$

=> $M_1 a = T - M_1gsin \theta_1 - \mu_1 M_1 g cos\theta_1$

Where T is the tension on the rope

The force acting on the mass $M_2$ is mathematically represented as

$F_2 = M_2gsin \theta_2 - T -\mu_2 M_2 g cos\theta_2$

$M_2 a = M_2gsin \theta_2 - T -\mu_2 M_2 g cos\theta_2$

At equilibrium

$F_1 = F_2$

$T - M_1gsin \theta_1 - \mu_1 M_1 g cos\theta_1 =M_2gsin \theta_2 - T -\mu_2 M_2 g cos\theta_2$

making a the subject of the formula

$a = \frac{M_2 g sin \theta_2 - M_1 g sin \theta_1 - \mu_1 M_1g cos \theta - \mu_2 M_2 g cos \theta_2 }{M_1 +M_2}$

substituting values $a = \frac{(5.45) (9.8) sin (32.5) - (2.25) (9.8) sin (43.5) - (0.205)*(2.25) *9.8cos (43.5) - (0.105)*(5.45) *(9.8) cos(32.5) }{2.25 +5.45}$

=> $a = 0.7156 m/s^2$

3 0

4 years ago

An Olympic runner competing in a long-distance event finishes with a time of 2 hours , 15 minutes , and 23 seconds . The event h

Talja [164]

Answer:

The average speed of the runner is 18.2 km/h.

Explanation:

Hi there!

The average speed is calculated as the traveled distance over time:

speed = traveled distance / elapsed time to cover that distance

We have to find the speed in km/h, so let´s start converting the time into hours:

23 s · (1 min/60 s) = 0.38 min

15.38 min · (1 h / 60 min) = 0.26 h

Total time: 0.26 h + 2 h = 2.26 h

The distance traveled in km is:

25.5 mi · (1.61 km/ 1 mi) = 41.1 km

Then, the average speed will be:

speed = 41.1 km / 2.26 h = 18.2 km/h

The average speed of the runner is 18.2 km/h.

6 0

3 years ago

Match the variables to its definition​

Match the variables to its definition