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Nuetrik [128]
3 years ago
8

If two parallel conductors are both free to move and are carrying current in the same direction, what would happen if the curren

t flow in each wire was reversed at the same time?A. The wires would repel, then attract each other. B. The wires would repel each other as they had before C. The wires would attract, then repel each other. D. The wires would remain attracted to each other.
Physics
1 answer:
pishuonlain [190]3 years ago
8 0

The wires would remain attracted to each other.

Option D.

Explanation:

It is known that magnetic flux will be generated in conductors with varying emf. So when current is flowing in two parallel conductors, the magnetic flux will be generated in those wires. If the current is flowing in same direction in both the wires, then the magnetic flux will be generated towards inside and outside the wires. Thus, the wire will get attracted to each other till the time the current is flowing in the same direction in both the wires. So if the current flow in each wire was reversed at the same time, then the wire would remain attracted to each other.

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Help? I don't know how to do this.
aliya0001 [1]

Use the definition of acceleration:

Acceleration = (change of velocity) divided by (time for the change)

The graph says:

Change of velocity = -6 m/s

Time for the change = 3 sec

So Acceleration = (-6m/s) / (3 s)

That's -6/3 m/s•s

or

-2 m/s^2

5 0
3 years ago
How do i figure out this question?
nikklg [1K]

Answer:

0.75 g/cm^3

Explanation:

The formula for density:

\rho = \frac{m}{V}

Where m is the mass and V is the volume.

So, we can substitute values for m and V:

\rho = \frac{277}{370}\approx0.75

Therefore, the density is 0.75 g/cm^3 (watch the units!)

8 0
3 years ago
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How to find the gradient of a velocity time graph
Sidana [21]
The area-

The area under the line in a velocity-time graph represents the distance travelled. To find the distance travelled in the graph above, we need to find the area of the light-blue triangle and the dark-blue rectangle.

<span><span>Area of light-blue triangle -
<span>The width of the triangle is 4 seconds and the height is 8 meters per second. To find the area, you use the equation: <span>area of triangle = 1⁄2 × base × height </span><span>so the area of the light-blue triangle is 1⁄2 × 8 × 4 = 16m. </span></span></span><span> Area of dark-blue rectangle The width of the rectangle is 6 seconds and the height is 8 meters per second. So the area is 8 × 6 = 48m.</span><span> Area under the whole graph <span>The area of the light-blue triangle plus the area of the dark-blue rectangle is:16 + 48 = 64m.<span>This is the total area under the distance-time graph. This area represents the distance covered.</span></span></span></span>
7 0
3 years ago
A baseball rolls off a 1.20m high desk and strikes the floor 0.50m away from the base of the desk . How fast was it rolling?
noname [10]

The initial velocity of the ball is 1.01 m/s

Explanation:

The motion of the ball rolling off the desk is a projectile motion, which consists of two independent motions:

- A uniform horizontal motion with constant horizontal velocity

- A vertical accelerated motion with constant acceleration (g=9.8 m/s^2, acceleration due to gravity)

We start by analyzing the vertical motion: we can find the time of flight of the ball by using the following suvat equation

s=ut+\frac{1}{2}gt^2

where

s = 1.20 m is the vertical displacement (the height of the desk)

u = 0 is the initial vertical velocity

g=9.8 m/s^2

t is the time of flight

Solving for t,

t=\sqrt{\frac{2s}{g}}=\sqrt{\frac{2(1.20)}{9.8}}=0.495 s

Now we analyze the horizontal motion. We know that the ball covers a horizontal distance of

d = 0.50 m

in a time

t = 0.495 s

Therefore, since the horizontal velocity is constant, we can calculate it as

v_x = \frac{d}{t}=\frac{0.50}{0.495}=1.01 m/s

So, the ball rolls off the table at 1.01 m/s.

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

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3 years ago
What type of energy is sunlight referred as?
nordsb [41]
The sun's energy is refferd to solor energy
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3 years ago
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