$x+3y=5 \ =>\boxed{x=5-3y} \\\\ 2x+y=5 \\\\ 2(5-3y)+y=5 \\\\10-6y+y=5 \\\\ -5y=5-10 \\\\ -5y=-5 \ |:(-5) \\\\ \boxed{y=1} \\\\ x=5-3*1 \\\\ x=5-3 \\\\ \boxed{x=2}$

6 0

3 years ago

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The value of x-y is negative, and x and y are both positive. What can you conclude about the values of x

Stolb23 [73]

Well for two positive numbers subtracted to equal a negative number, the first number must have a value that is less than the second number. (Ex. 3-4= -1) In this case, you can conclude that x is less than y! (x<y)

3 0

3 years ago

if the statement "if it is snowing then it is cold outside" is assumed to be true is it reverse "if it is cold outsied then it i

Fofino [41]

No, the reverse is not always true, because it isn't always snowing outside when it's cold. However, if it's snowing outside, it must be cold as snow is, essentially, tiny bits of ice.

7 0

3 years ago

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If P(A)=12, P(A B)=16, and P(A B)=23, what is P(B)? 1/4 2/3 1/2 1/3

kolezko [41]

Answer:

P(B) 7

Step-by-step explanation:

The answer is P (B)

8 0

1 year ago