Answer:
as soon as possible
Step-by-step explanation:
and it an 90 degree angle
u have to add it
Given:
The figure of a rhombus QRST.
To find:
A. The value of x.
B. The measure of angle RQP.
Solution:
A. We need to find the value of x.
We know that the diagonals of a rhombus are perpendicular bisectors. It means the angles on the intersection of diagonals are right angles.
[Right angle]
Divide both sides by 5.
Therefore, the value of x is 15.
B. We need to find the measure of angle RQP.
From the given figure, it is clear that
Putting , we get
Therefore, the measure of angle RQP is 33 degrees.
Answer:
2.56 * 10^11 L
Step-by-step explanation:
1 body has 40 L
Thus, the amount in 6.4 billion would be;
40 * 6.4 * 10^9
= 256 * 10^9
= 2.56 * 10^2 * 10^9
= 2.56 * 10^11 L
Answer:
Step-by-step explanation:
Answer: A.) 2 <= X <= 6
B.) 13 < = X < = 39
Step-by-step explanation:
Given that a factory can work its employees no more than 6 days a week, that is, less than or equal to 6 days a week
And also, no less than 2 days per week. That is, greater than or equal to 2 day a week.
Let X represent the number of days an employee can work per week.
According to the first statement,
X < = 6
According to the second statement,
X >= 2
An inequality to represent the range of days an employee can work will be
2 < = X <= 6
To represent the range in hours, first convert the number of days to hour. Given that an employee can work
1 day = 6.5 hours
2 days = 2 × 6.5 = 13 hours
5 days = 6 × 6.5 = 39 hours
Therefore, the range will be
13 < = X < = 39
Answer:
11/50
Step-by-step explanation:
The frequency numbers for landing on 1, 2, and 3 are:
25, 53, 62.
We add them up to get: 25 + 53 + 62 = 140
Since 250 spins were made, and 140 of them landed on 1, 2, or 3, then
250 - 140 = 110,
so 110 landed on 4 or 5.
We are told the numbers of spins landing on 4 and 5 are equal, so
110/2 = 55,
so the spinner landed 55 times on 4 and 55 times on 5.
relative frequency = 55/250 = 11/50
