Answer:
Average power output of insect is 2.42W
Explanation:
Workdone by constant force during displacement is given by:
W= F× d cos theta
Where theta is angle between F and d.
Power output due to the force over the interval time is given by:
P= Workdone/change in time
Ginen:
Mass of insect,m= 7.0g= 7/1000 = 0.07kg
Downward force applied by insect,F= 2mg
Distance moved by the wing each stroke=1.5cm=1.5/100= 0.015m
W= F× d cos theta
Where theta=0° since force is in the same direction as the displacement.
W= 2mg×d
W= 2× 0.07 × 9.8 × 0.015
W= 0.02058J
Power output = W/ change in time
Since wings make 117strokes each second time interval is 1/117 = 8.5×10^-3seconds
Power= 0.02058/(8.5×10^-3)
Power= 2.42W
Given that,
mass m= 5.7 kg
Force of gravity = ?
Since,
Force of gravity acting on earth is equal to the weight and
W= mg
W= 5.7 * 9.81
W= 55.917
or
W= 56 N
Force of gravity acting on Earth by the package is 56 N.
Answer:
<em>Asha traveled a distance of 50 m</em>
<em>The displacement is 20 m north.</em>
Explanation:
<u>Distance and Displacement
</u>
A moving object constantly travels for some distances at defined periods of time. The total moved distance is the sum of each individual distance the object traveled. It can be written as:
dtotal=d1+d2+d3+...+dn
This sum is obtained independently of the direction the object moves.
The displacement only takes into consideration the initial and final positions of the object while moving. The displacement, unlike distance, is a vectorial magnitude and can even have magnitude zero if the object starts and ends the movement at the same point.
Asha walks 15 m west, 20 m north, and 15 m east. The total distance is
dt=15 m + 20 m + 15 m = 50 m
Asha traveled a distance of 50 m
Note the final position is 20 m above the initial position since she goes 15 m west and 15 m east. Thus the displacement is 20 m north.
Answer:the answer would be C.50N
Explanation:I just took the test
Answer:
0.2286 m, 0.686 m and 1,143 m
therefore we see that there is respect even where the intensity is minimal
Explanation:
Destructive interference to the two speakers is described by the expression
Δr = (2n +1) λ/2
where r is the distance, λ the wavelength and n an integer indicating the order of the interference
let's locate the origin on the left speaker
let's find the wavelength with the equation
v = λ f
λ = v / f
we substitute
Δr = (2n + 1) v / 2f
let's calculate for difference values of n
Δr = (2n +1) 343/(2 750)
Δr = (2n + 1) 0.2286
we locate the different values for a minimum of interim
n Δr (m)
0 0.2286
1 0.686
2 1,143
therefore we see that there is respect even where the intensity is minimal
