All categories

3 years ago

You push a 15 kg box with a force of 80 N. If the force of friction is 63 N, what will its acceleration be?

Physics

1 answer:

alina1380 [7]3 years ago

3 0

Answer:

1.13m/s²

Explanation:

F-Fk = Fr

Fr = 80 - 63 = 17N

Fr = ma

a = Fr/m = 17/15 = 1.13m/s²..

don't forget to like

You might be interested in

A student launches a small 0.5 kg rocket with an initial speed of 30 m/s at an angle of 60°. Approximately how much time will th

Elena L [17]

Answer:

$t=5.30s$

Explanation:

The high reached by a proyectile in an uniformly accelerated motion is given by:

$y=v_{0y}t-\frac{gt^2}{2}$

The time that the rocket spends in the air is obtained for y = 0, since this is the time that the rocket travels before touching the ground. Recall that $v_{0y}=v_0sin\theta$ . Solving for t:

$0=(v_0sin\theta) t-\frac{gt^2}{2}\\\frac{gt}{2}=v_0sin\theta\\t=\frac{2v_0sin\theta}{g}\\t=\frac{2(30\frac{m}{s})sin(60^\circ)}{9.8\frac{m}{s^2}}\\t=5.30s$

5 0

4 years ago

Which are true for a photon. (Choose 3)

SVEN [57.7K]

The last one

Xjjxueuwuduchjdnrnn Brendan hush she j

6 0

3 years ago

Two nuclear reactors provide 3200 MW of power.If the transmission system loses 5.1% of the energy produced,how much power from t

Annette [7]

The power that the customers receive is 163.2 MW

Explanation:

The efficiency of a system is given by

$\eta = \frac{P_{out}}{P_{in}}$

where

$P_{out}$ is the power in output

$P_{in}$ is the power in input

For the nuclear reactors in this problem, we have:

$P_{in} = 3200 MW$ (power generated by the reactors)

$\eta=0.051$ (efficiency is 5.1%)

Therefore, the power that reaches the customers is:

$P_{out} = \eta P_{in} = (0.051)(3200)=163.2 MW$

Learn more about power:

brainly.com/question/7956557

#LearnwithBrainly

6 0

3 years ago

What is the empirical formula of a compound that contains 27.0% s

eduard

Answer:

Empirical formula of the compound = SOCl₂

Explanation:

QUESTION:What is the empirical formula of a compound that contains 27.0% S, 13.4% O, and 59.6% Cl by mass?

The empirical formula of a compound is its simplest formula. It tells us

* The component element present in a molecule of the compound.

* The ratio in which these elements are combined together, i.e mole ratio.

To calculate the empirical formula of a compound that contains 27.0% S, 13.4% O, and 59.6% Cl by mass. ( Relative atomic mass of S=32gmol⁻¹, 0=16gmol⁻¹, Cl=35.5gmol⁻¹)

Sulphure S, Oxygen O, Chlorine Cl

percentage by mass: 27.0% 13.4% 59.6%

Step 1:

Divide by their relative

atomic mass: 27.0/32.0 13.4/16.0 59.6/35.5

⇒⇒⇒⇒⇒⇒⇒⇒⇒ 0.844 0.838 1.679

Step 2:

Divide by the

smallest mole ratio: 0.844/0.838 0.838/0.838 1.679/0.838

∴ 1 : 1 : 2.

from the analysis above, the compound contains Sulphur, Oxygen and Chlorine in the ratio of 1:1:2.

∴ Empirical formula of the compound = SOCl₂

6 0

3 years ago

When a fisher casts his line into the water, the location where he sees the fish is not actually where the fish is, due to refra

Dennis_Churaev [7]

The fish is actually farther from you then you think

8 0

3 years ago