initial velocity = 0 = v₍i₎
final velocity = ? = v₍f₎
t = 12 sec
Acceleration = 4m/s²
First we have to find the distance d, for this we use the
formula,
D = v₍i₎t + 1/2at²
D = 0(12) + ½ (4)(12)²
Distance = d = 288 m
Now to find the Vf use the formula,
V₍f₎² = v₍i₎² + 2ad
V₍f₎² = (0)2 + 2(4)(288)
V₍f₎² = 2304
V₍f₎ = 48 m/s
so the velocity at the end of 12 sec is 48 m/s
Answer:
there it is fella u were right with ur answer
Answer:
Yes i am agree with this suggestion
Explanation:
Given that we have to assume that there is no any frictional affects.
As we know that when height increases then the discharge level will decreases when discharge level decreases then the time of filling for the bucket will increase.So the bucket will fill faster if the hose lowered until knee level.
Yes i am agree with this suggestion
Answer:
The object will contine to fall, but at a constant velocity. There will be no more acceleration.
Explanation: When the force of gravity is equal to the reverse force of air resistance, there will will be no net force on the falling obect. F = ma, and F (net) = 0. It will continue at the same speed until those forces become imbalanced again (such as when the force pushing up from the ground is greater than the force of gravity pulling it down). The metric term for this sudden resistance is "crash/bang/clunk/yieouch."
Answer: 0.16Hz
Explanation:
Given that:
wavelength (λ) = 125 meters
speed (V) = 20 m/s
frequency (F) = ?
Recall that frequency is the number of cycles the wave complete in one second. And its value depends on the wavelength and speed of the wave.
So, apply the formula V = F λ
Make F the subject formula
F = V / λ
F = 20 m/s / 125 meters
F = 0.16 Hz
Thus, the frequency of the wave is 0.16 Hertz.
