1) 1025km per 13.5hr = 1025km/13.5hr = 75.9 km/hr
2) 400km per 30min = 400km/30min = 13.3 km/min
13.3km/min X (60min per hr) = 13.3km/min(60min/hr) = 800km/hr
3) 45km/hr in 40min = 45km/hr X 40min X (1hr/60min) = 30km.
<span>
4) (30m/s - 10m/s) per 10s = 20m/s/10s = 2ms/s = 2m/s/s = 2m/s^2 </span>
As we know that mass of the box is given as
m = 9.5 kg
acceleration of the box is given as
so by Newton's II law we can say
now we can substitute all the values in it
So it required 9.5 N force to slide it
Answer:
Explanation:
First we need to determine the distance covered during deceleration. According to the equation of motion.
S = ut+1/2at²
Given:
u = 20m/s
t = 0.50s
a = -10m/s (deceleration is negative acceleration)
S = 20²+1/2(-10)(0.5)²
S = 400-5(0.5)²
S = 400-5(0.25)
S = 400-1.25
S = 398.75m
If the deer steps onto the road 35m in front of you, the distance between you and the deer when you come to a stop will be 398.75-35 = 363.75m
Answer:
I = 21.13 mA ≈ 21 mA
Explanation:
If
I₁ = 5 mA
L₁ = L₂ = L
V₁ = V₂ = V
ρ₁ = 1.68*10⁻⁸ Ohm-m
ρ₂ = 1.59*10⁻⁸ Ohm-m
D₁ = D
D₂ = 2D
S₁ = 0.25*π*D²
S₂ = 0.25*π*(2*D)² = π*D²
If we apply the equation
R = ρ*L / S
where (using Ohm's Law):
R = V / I
we have
V / I = ρ*L / S
If V and L are the same
V / L = ρ*I / S
then
(V / L)₁ = (V / L)₂ ⇒ ρ₁*I₁ / S₁ = ρ₂*I₂ / S₂
If
S₁ = 0.25*π*D² and
S₂ = 0.25*π*(2*D)² = π*D²
we have
ρ₁*I₁ / (0.25*π*D²) = ρ₂*I₂ / (π*D²)
⇒ I₂ = 4*ρ₁*I₁ / ρ₂
⇒ I₂ = 4*1.68*10⁻⁸ Ohm-m*5 mA / 1.59*10⁻⁸ Ohm-m
⇒ I₂ = 21.13 mA
Answer:
<em> 3980.89 ohms</em>
Explanation:
The capacitive reactance is expressed as;
f is the frequency
C is the capacitance of the capacitor
Given
f = 60H
C = C1+C2 (parallel connection)
C = 15μF + 25μF
C = 40μF
C = 
Substitute into the formula:
<em>Hence the total capacitive reactance is 3980.89 ohms</em>
