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Kamila [148]
3 years ago
12

Assume that you have to prepare a 200 g salt solution, and the concentration must be 15 % by mass. How many grams of solute and

water you must mix together.
Chemistry
1 answer:
Marrrta [24]3 years ago
3 0

Answer:

170 g

Explanation:

w/w% concentration = mass of solute/ mass of solution * 100

mass of solute = x

mass of solution = 200 g

w/w% concentration =  15 % by mass

15 = x/200 * 100

15 = 100x/200

200 * 15 = 100x

x = 200 * 15/100

x = 2 * 15

x = 30g

But mass of solution = mass of solute + mass of solvent

mass of solute = 30g

mass of solvent = mass of solution  - mass of solute

mass of solvent = 200 g - 30 g

mass of solvent = 170 g

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Explanation:

It is known that pK_{a} value of acetic acid is 4.74. And, relation between pH and pK_{a} is as follows.

                    pH = pK_{a} + log \frac{[CH_{3}COOH]}{[CH_{3}COONa]}

                          = 4.74 + log \frac{1.00}{1.00}

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Hence, addition of sodium acetate in NaOH will lead to the formation of acetic acid as follows.

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Initial :    1.00 mol                                  1.00 mol

NaoH addition:               0.05396 mol

Equilibrium : (1 - 0.05396 mol)    0           (1.00 + 0.05396 mol)

                    = 0.94604 mol                       = 1.05396 mol

As, pH = pK_{a} + log \frac{[CH_{3}COONa]}{[CH_{3}COOH]}

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                         pH = 4.74 - 4.69

                               = 0.05

Thus, we can conclude that change in pH of the given solution is 0.05.

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