First we use product rule
y=x^2lnx
dy/dx = x^2 d/dx (lnx) + lnx d/dx (x^2)
dy/dx = x^2 (1/x) + lnx (2x)
dy/dx = x + 2xlnx
now taking second derivative:
d2y/dx2 = 1 + 2[x (1/x) + lnx (1)]
d2y/dx2 = 1 + 2[1+lnx]
1+2+2lnx
3+2lnx is the answer
Answer:
option A
Step-by-step explanation:
2*5*3, you still get the same answer as (3*2)*5
Answer:
The answer is C
Hope this helps!
Mark me brainliest if I'm right ;)
Answer:
(0,4) and (-2,0)
Step-by-step explanation:
y=3x²+4x+4
y = -2x +4
3x²+4x+4 = - 2x +4
3x²+6x=0
3x(x+2)=0
x=0, x= -2
x=0, y=-2x+4= -2*0 + 4 =4, (0,4)
x= - 2, y = 2x + 4= 2*(-2) +4=0, (-2,0)
