All categories

3 years ago

Solve the equation −96=3(8x)^(5/3).

Mathematics

1 answer:

vladimir2022 [97]3 years ago

5 0

Answer:

x= - 1

Step-by-step explanation:

You might be interested in

the point P = (x, 1/2) lies on the unit curcle shown below. what is the value of x in the simplest form

Mrac [35]

Answer:

x=sqrt(3)/2 or -sqrt(3)/2

Step-by-step explanation:

(x,1/2) is on the unit circle at pi/6 and 5pi/6.

so x is either sqrt(3)/2 or -sqrt(3)/2

5 0

4 years ago

The cancellation property sin−1(sin(x)) = x is valid for x in what interval

pochemuha

Answer:

It is given that : $Sin^{-1}(Sin (x) =x$

As we have to find the Domain of $Sin^{-1}(Sin (x)$ .

-1 ≤ sin x ≤1

$Sin^{-1}(-1)\leq Sin^{-1}(Sin x)\leq Sin^{-1}(1)\\\frac{-\pi}{2}\leq x\leq \frac{\pi }{2}$

So it is defined for x lying between $(\frac{-\pi}{2}, \frac{\pi }{2})$ .

As meaning of Domain is those values of x for which any function f(x) is defined.

4 0

3 years ago

The value of 8 in 8596 is how many times the value of 8 in 485

Effectus [21]

It is 100x because 80x100=8,000

6 0

3 years ago

Ricardo has 2 cases of video games Edith the same number of games in each case. He gives 4 games to his brother. Ricardo has 10

alisha [4.7K]

Answer:

7 games

Step-by-step explanation:

Ricardo has 2 cases with x number of games in each. This means 2x is the amount of video games in both. He gives away 4. He now has 2x-4 and has 10 left. This is 2x-4=10. Solve for x.

2x - 4 = 10

2x = 14

x=7

7 0

3 years ago

In 1990, 23.8% of 18-24 year-olds in Biddeford, Maine were attending college. About 10 years later, a random sample of 610 18-24

Vlada [557]

Answer:

There is enough evidence to support the claim that the percentage of residents attending college in that age-group is greater than 23.8%

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 610

p = 23.8% = 0.238

Alpha, α = 0.01

Number of 18-24 year-old attending college , x = 178

First, we design the null and the alternate hypothesis

$H_{0}: p = 0.238\\H_A: p > 0.238$

This is a one-tailed(right) test.

Formula:

$\hat{p} = \dfrac{x}{n} = \dfrac{178}{610} = 0.2918$

$z = \dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}$

Putting the values, we get,

$z = \displaystyle\frac{0.2918-0.238}{\sqrt{\frac{0.238(1-0.238)}{610}}} = 3.1201$

Now, we calculate the p-value from the table.

P-value = 0.0009

Since the p-value is lower than the significance level, we fail to accept the null hypothesis and reject the null hypothesis.

Conclusion:

Thus there is enough evidence to support the claim that the percentage of residents attending college in that age-group is greater than 23.8%

4 0

4 years ago

Read 2 more answers