<u>Answer:</u>
1 cm : 10.5 km
<u>Step-by-step explanation:</u>
We are given that two towns are 31.5 km in real and are 3 cm apart on a map and we are to find the scale of the map.
For this, we can use the ratio method.



Therefore, the scale of the map would be 1 cm : 10.5 km.
Answer:
The Graph Shifts 4 units up
Step-by-step explanation:
Okay so, when you add four to a graph in this manner we have to look at the equation as a whole. f(x)=mx+b + 4. By adding four we are changing the y-intercept and shifting it up four. This will cause the entire graph to shift upwards four spaces.
480
This is this awnser because its 120 a second, for 4 seconds so 4 times 120 = 480.
Answer:
• multiplied by 4p: (x -h)² +4pk = 0
• zeros for k > 0: none
• zeros for k = 0: one
• zeros for k < 0: two
Step-by-step explanation:
a) Multiplying by 4p removes the 1/(4p) factor from the squared term, but adds a factor of 4p to the k term. (It has no effect on the subsequent questions or answers, so we wonder why we're doing this.) The result is ...
(x -h)² +4pk = 0
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b) The value of k is the vertical location of the vertex of the parabola with respect to the x-axis. The parabola opens upward, so for k > 0, the parabola does not cross the x-axis, and the number of real zeros is zero. (There are two complex zeros.)
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c) As in part b, the value of k defines the vertex location. When it is zero, the vertex of the parabola is on the x-axis, so there is one real zero (It is considered to have multiplicity 2.)
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d) As in part b, the value of k defines the vertex location. When it is negative, the vertex of the parabola is below the x-axis. Since the parabola opens upward, both branches will cross the x-axis, resulting in two real zeros.
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The attached graph shows a parabola with p=1/4 and h=2. The values shown for k are +1, 0, and -1. The coordinates of the real zeros are shown.
Answer:
c = 5
Step-by-step explanation:
A quadratic equation in standard form is
ax² + bx + c = 0 : a ≠ 0
Given
- 6 = x² + 4x - 1 ( add 6 to both sides )
0 = x² + 4x + 5 ← in standard form
with c = 5