Let 2x – y = 3 ——— equation 1
Let x + 5y = 14 ——— equation 2
Making x the subject in eqn 1, = x = y + 3 / 2 ——— eqn 3
• Put eqn 3 in eqn 2
(y + 3 / 2) + 5y = 14
6y = 14 – 3/2
6y = 25/2
y = 25/12
• put y = 25/12 in eqn 3
x = (25/12 + 3/2)
x = 43/12
I think is inside and then outside. Not sure
Hope this helps!
6*8 = 22
They Multiplied The Second Number By Two Then Added The First Number To It.
Answer:
The third one
Step-by-step explanation:
