I think its either b. or d. i know its not a. It might be B. hope this helps?
Answer:
The velocity of Mosquito with respect to earth will be 0.302m/s
Explanation:
V(ma) = 1.10 m/s, east Velocity of mosquito with respect to air
V(ae) = 1.4 m/s at 35° Velocity of air with respect to Earth in west of south direction.
Velocity of Mosquito with respect to earth will be
V(me) = V(ma) + V(ae)
We need to find the mosquito’s speed with respect to Earth in the x direction.
V(x, me) = V(x, ma) + V(x, ae) = V(ma) + V(ae)(cos theta(ae) )
Angle (ae) = –90.0° − 35°=−125°
V(x, me) = 1.10 + (1.4)Cos(-125)
= 1.10 + 1.4(-0.57)
= 1.10 -0.798
= 0.302
So the velocity of Mosquito with respect to earth will be 0.302m/s
Answer:
The light ray is reflected back into the opposite direction
Explanation:
The law of reflection states that when a light ray hits a reflecting surface, the angle of reflection (measured between the reflected ray and the normal to the surface) is equal to the angle of incidence (measured between the incident ray and the normal to the surface).
In this case, we have a light ray that it is incident along the normal to the surface: this means that the angle of incidence is . As per the law of reflection, the angle of reflection must be the same: . This means that the reflected ray is also along the normal, just in the opposite direction to that of the incident ray.
To solve this problem we will apply the concepts of speed given the simple harmonic movement, for which it defines this speed as
Here
Angular velocity
A = Amplitude
Recall that the angular velocity is equivalent in terms of the frequency at
If we replace the value we will have then
<em>For mass A </em>
<em>For mass B </em>
Therefore they are equal.