Answer:
Correct answer: V₁ boat = 16 km/h and V₂ current = 4 km/h
Step-by-step explanation:
If we take speed (velocity) of the boat as V₁ and speed of the current V₂
Let us form equations:
Traveling down the current V₁ + V₂ = 60/3 = 20 km/h
Traveling against the current V₁ - V₂ = 60/5 = 12 km/h
V₁ - V₂ = 12
V₁ + V₂ = 20
If we add up the left and right sides of the equations we get:
2 V₁ = 32 => V₁ = 32/2 = 16 km/h
from the second equation we get:
V₂ = 20 - V₁ = 20 - 16 = 4 km/h
V₂ = 4 km/h
God is with you!!!
First one: If the leading coeff. is negative, the graph begins in Quadrant III and ends in Quadrant IV. It's an even function. The fourth graph represents it.
If the leading coeff. is positive, but everything else remains the same, the graph opens upward, beginning in Q II and ending in Q I.
Answer:
Step-by-step explanation:
SIDE OF THE SQUARE = 6 cm = DIAMETER OF THE CIRCLE.
AREA OF THE CIRCLE = (Pi/4)*6^2 = [(22/7)/4]*36 = 22*9/7 = 28.2857 sqcm
or
First, find the side length of the square. (Find the square root of 36 cm^2, to get 6 cm as the side length of the square).
Second, find the radius of the circle inside the square. The side length of the square is the diameter of the circle. Radius is half of the diameter. So, half of 6 cm is 3 cm; this is the radius of the circle.
Third, find the area of the circle by using the formula, A = pi x radius x radius
so, Area = 3.14 x 3 cm x 3 cm
by calculation we get the area of the circle is 28.26 cm^2
Where pi is a constant of 22/7 or 3.14
X | Y
-------
-5| 10
-4| 8
-3| 6
-2| 4
-1| 2
0 | 0
1 | -2
2 | -4
3 | -6
4 | -8
5 | -10
Both are correct.
Good job!
