When particles collide with the surface of the solid.
5.50M NaOH must be added to 680.0 mL of a buffer, The amount of NaOH is mathematically given as
V=2.107mL
<h3>What is the volume of 5.50M NaOH?</h3>
Generally, the equation for Chemical Reaction is mathematically given as
CH3COOH+OH^{-} ⇄ CHCOO^{-} + H2O
Therefore
pka=-log(1.8*10{-5})
pKa=5-0.25527
pKa=4.3447
Hence
x=0.0115898
Volume of NaOH
V=0.0021072L
V=2.107mL
Read more about Chemical Reaction
brainly.com/question/11231920
#SPJ1
Lets assume that 100 grams of the compound are present.
Carbon mass: 88.14 g
Hydrogen mass: 11.86 g
Moles carbon: 88.14/12 = 7.34
Moles hydrogen: 11.86/1 = 11.86
The moles of carbon are 7.34 and the moles of hydrogen are 11.86.
Answer:
D. 23.9 liters
Explanation:
- Molarity is defined as the no. of moles of solute dissolved in 1.0 L of the solution.
M = (no. of moles)solute / (V of the solution (L))
M = (mass/molar mass)NaCl / (V of the solution (L))
M = 0.03 M, mass of NaCl = 42.0 g, molar mass = 58.44 g/mol.
∴ V of the solution = (mass/molar mass)NaCl / M = [(42.0 g/58.44 g/mol)] / (0.03 M) = 23.96 L.
<em>So, the right choice is: D. 23.9 liters</em>
Answer:
3 electrons are gained by one nitrogen atom in the formation of K₃N.
Explanation:
The reaction is as follow,
<span> 6 K + N</span>₂<span> </span>→ <span> 2 K</span>₃<span>N
</span>
Oxidation of K,
K → K⁺ + 1 e⁻
Or,
6 K → 6 K⁺ + 6 e⁻
In oxidation reaction potassium atom transfers one electron per atomn and six electrons per six atoms.
Reduction of N;
N₂ + 6 e⁻ → 2 N³⁻
In reduction reaction one molecule of N₂ gains six electrons and 3 electrons per one atom
