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SashulF [63]
2 years ago
10

A sample of pure NO2 is heated to 335 ∘C at which temperature it partially dissociates according to the equation 2NO2(g)⇌2NO(g)+

O2(g) At equilibrium the density of the gas mixture is 0.525 g/L at 0.750 atm .
Chemistry
1 answer:
vodka [1.7K]2 years ago
5 0

The equilibrium constant for the reaction is 0.00662

Explanation:

The balanced chemical equation is :

2NO2(g)⇌2NO(g)+O2(g

At t=t  1-2x ⇔ 2x + x moles

The ideal gas law equation will be used here

PV=nRT

here n= \frac{w}{W} = \frac{w}{V}= density

P = \frac{density RT}{M}       density is 0.525g/L, temperature= 608.15 K, P = 0.750 atm

putting the values in reaction

0.75 = \frac{0.525 x 0.0821 x 608.15 }{M}

  M    = 34.61

         

to calculate the Kc

Kc=\frac{ [NO] [O2]}{NO2}

  \frac{1-2x}{1+x} x M NO2 + \frac{2x}{1+x} M NO+ \frac{x}{1+x} M O2

Putting the values as molecular weight of NO2, NO,O2

\frac{46(1-2x) +30(2x)+32x}{1+x}

34.61= \frac{46}{1+x}

x= 0.33

Kc= \frac{4x^2)x}{1-2x^2}

    putting the values in the above equation

Kc = 0.00662

     

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Answer: The correct option is (c). The total pressure doubles.

Solution:

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p_{O_2}=Tp_1\times X_{O_2}  (X_{O_2}=\frac{4}{4}) ( according to Dalton's law of partial pressure)

p_{O_2}=Tp_1\times 1=Tp_1....(1)

Tp_1= Total pressure when only oxygen gas was present.

Final total pressure when 4 moles of helium gas were added:

X'_{O_2}=\frac{4}{8}=\farc{1}{2},X_{He}=\frac{4}{8}=\frac{1}{2}

partial pressure of oxygen in the mixture :

Since, the number of moles of oxygen remains the same, the partial pressure of oxygen will also remain the same in the mixture.

p_{O_2}=Tp_2\times X'_{O_2}=Tp_2\times \frac{1}{2}

Tp_2= Total pressure of the mixture.

from (1)

Tp_1=Tp_2\times X'_{O_2}=Tp_2\times \frac{1}{2}

On rearranging, we get:

Tp_2=2\times Tp_1

The new total pressure will be twice of initial total pressure.

7 0
3 years ago
A saline solution with a mass of 400 g has 30 g of NaCl dissolved in it. What is the mass/mass percent concentration of the solu
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hope this helps!

3 0
3 years ago
A sample of 0.600 mol of a metal m reacts completely with excess fluorine to form 46.8 g of mf2. how many moles of f are in the
oksian1 [2.3K]
The balanced chemical reaction is expressed as:

M + F2 = MF2

To determine the moles of the element fluorine present in the product, we need to determine the moles of the product formed from the reaction and relate this value to the ratio of the elements in MF2. We do as follows:

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6 0
3 years ago
Lewis structure for nitrogen triiodide, NI(3)
Rasek [7]

Answer:

Lewis structure for nitrogen triiodide,NI_3 is given in the attachment.

Explanation:

Given:

The given compound is Nitrogen triiodide. In which 1 atom of Nitrogen combines with 3 atoms of Iodine. Both Nitrogen and Iodine are non-metals,So they form covalent bond by sharing of electrons.

The electron configuration of Nitrogen and Iodine is given below;

N(7) = 1s^2,2s^22p^3\\I(53) = 1s^2,2s^22p^6,3s^23p^63d^{10},4s^24p^64d^{10},5s^25p^5

There are 5 electrons in valance shell of Nitrogen atom and 7 electrons in valance shell of Iodine atom.

So, 3 atom of Iodine shares 1 electron with 1 electrons of Nitrogen.

The Lewis dot Structure is in the attachment.

3 0
3 years ago
What coefficients should be added in order to make this a balanced equation?
Vanyuwa [196]

Answer:

Hello

Coefficients are 1,3,2,1

Explanation

6 0
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