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Rus_ich [418]
3 years ago
15

Please select the word from the list that best fits the definition the characteristic temperature at which a pure solid changes

to a liquid is its ______ point.
Chemistry
1 answer:
nirvana33 [79]3 years ago
3 0
The answer is melting
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Extend your thinking: Why do you think the temperature does not change much during a phase change?
Hatshy [7]

Answer:

Look in explanation:

Explanation:

The definition of temperature is the measure of kinetic energy(which is the energy used to measure motion). Since phase changing is only changing the energy, the kinetic energy will not change. There is only energy used to separate the molecules. You can see on a phase change graph that the temperature stays constant during a phase change and will ONLY change after the change has already been done.

5 0
3 years ago
2) All forms of radioisotopes:
Anarel [89]
The answer is the letter d
7 0
3 years ago
Read 2 more answers
PLS help I will give 100 points
goldenfox [79]

Answer:

3700000000

Explanation: Move decimal to the right of the amount the exponent is for 10 Give brainliest pls

4 0
3 years ago
Oxalic+acid+is+a+toxic+substance+used+by+laundries+to+remove+rust+stains.+its+composition+is+26.7%+c,+2.2%+h,+and+71.1%+o+(by+ma
Anettt [7]

The molecular formula of a compound is C₂H₂O₄.

Take 100 grams of compound:

1) ω(C) = 26.7% ÷ 100% = 0.267

m(C) = ω(C) × m(compound)

m(C) = 0.267 × 100 g.

m(C) = 26.7 g.

n(C) = m(C) ÷ M(C).

n(C) = 26.7 g ÷ 12 g/mol.

n(C) = 2.22 mol; amount of carbon

2) ω(H) = 2.2 % ÷ 100% = 0.022

m(H) = 0.022 × 100 g.

m(H) = 2.2 g.

n(H) = 2.2 g ÷ 1 g/mol.

n(H) = 2.2 mol; amount of hydrogen

3) ω(O) = 71.1 % ÷ 100%.

ω(O) = 0.711

m(O) = 0.711 × 100 g

m(O) = 71.1 g

n(O) = 71.1 g ÷ 16 g/mol

n(O) = 4.4 mol; amount of oxygen

4) n(C) : n(H) : n(O) = 2.2 mol : 2.2 mol : 4.4 mol /2.2 mol.

n(C) : n(H) : n(O) = 1 : 1 : 2

M(CHO₂) = 45 amu; empirical formula

90 amu ÷ 45 amu = 2 CHO₂

More info about empirical formula: brainly.com/question/1873039

#SPJ4

5 0
1 year ago
A certain solid has a density of 8.0 g/cm3. if 4.0 g of this solid are poured into 4.00 ml of water, which drawing below most cl
Alexandra [31]
Answer is: <span>the volume of water after the solid is added</span> is 4.5 ml.
d(gold) = 8.0 g/cm³; density of gold.
m(gold) = 4 g; mass of gold.
V(gold) = m(gold) ÷ d(gold); volume of gold.
V(gold) = 4 g ÷ 8 g/cm³.
V(gold) = 0.5 cm³ = 0.5 ml.
V(water) = 4.00 ml = 4.00 cm³.
V(flask) = V(gold) + V(water).
V(flask) = 0.5 cm³ + 4 cm³.V = 4.5 cm³.
4 0
3 years ago
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