Answer: The mole fraction of methanol
Xmeth= 0.59
The mole fraction of ethanol
Xeth = 0.41
Explanation:
Mole fraction of a component can be determined by:
Xi = moles of i / total moles of the components the components
Where i indicates the component
An equal mass of 100.0g is assumed for both methanol and ethanol
Molar mass of Methanol (CH4O)
= (1*12) + (4*1) +(1*16) =32g/mol
Mole of Methanol = mass of methanol /molar mass of methanol
=100/32 = 3.13mol.
Molar mass of ethanol ( C2H6O)
= (2*12)+(6*1)+(1*16) = 46.0g/mol
Mole of ethanol = 100/46
= 2.17mol.
Mole fraction of methanol (Xmeth)
= moles of methanol / total moles
Xmeth = 3.13/(3.13+2.17)
Xmeth = 0.59
Mole fraction of ethanol (Xeth)
= moles of ethanol /total moles
= 2.17/((3.13+2.17)
Xeth= 0.41
