We have a solution of NaOH and H₂CO₃
First, NaOH will dissociate into Na⁺ and OH⁻ ions
The Na⁺ ion will substitute one of the Hydrogen atoms on H₂CO₃ to form NaHCO₃
The H⁺ released from the substitution will bond with the OH⁻ ion to form a water molecule
If there were to be another NaOH molecule, a similar substitution will take place, substituting the second hydrogen from H₂CO₃ as well to form Na₂CO₃
Answer:
a)
b)
c)
Explanation:
a)
when is added to LiOH, lithium chlorate and water is formed.
Balancing of above reaction,
It can be seen that all the atoms in both the sides are balanced. so it is a balanced reaction.
(b) When aqueous is added to NaOH,
and
is formed. It is a neutrilization reaction.
Balancing of above reaction,
First balance all the atoms except O and H
S atom is already balanced in either side
No. of Na atom in left hand side = 1
No. of Na atom in right hand side = 2
So multiply NaOH by 2, now the reaction becomes:
No. of O atoms in left hand side = 6
No. of O atoms in right hand side = 5
So multiply H2O by 2, now the reaction becomes:
Now, it can been seen that all the atoms are balanced.
c) When reacts with HF, baroum fluoride and water is formed.
Balancing of above reaction,
Barium atoms are already balanced on either side.
No. of F atoms on left hand side = 1
No. of F atoms on right hand side = 2
So, multiply HF by 2, now reaction becomes
In order to balance H and O on either side, multiply H2O by 2.