The given statement, some type of path is necessary to join both half-cells in order for electron flow to occur, is true.
Explanation:
Flow of electrons is possible with the help of a conducting medium like metal wire.
A laboratory device which helps in completion of oxidation and reduction-half reactions of a galvanic or voltaic cell is known as salt bridge. Basically, this salt bridge helps in the flow of electrons from anode to cathode and vice-versa.
If salt bridge is not present in an electrochemical cell, the electron neutrality will not be maintained and hence, flow of electrons will not take place.
Thus, we can conclude that the statement some type of path is necessary to join both half-cells in order for electron flow to occur, is true.
Answer:
17.1195 grams of nitric acid are produced.
Explanation:
Moles of nitrogen dioxide :
According to reaction 3 moles of nitrogen dioxides gives 2 moles of nitric acid.
Then 0.5434 moles of nitrogen dioxides will give:
of nitric acid.
Mass of 0.3623 moles of nitric acid :
Theoretical yield = 22.8260 g
Experimental yield = ?
Experimental yield of nitric acid = 17.1195 g
Explanation:
As the given chemical reaction equation is as follows.
Also, it is given that for 2 moles the energy required is 130 kcal. This means that energy required for 1 mole is calculated as follows.
1 mole = 
= 65 kcal
Hence, energy required for 7 moles will be calculated as follows.
Energy required = 
= 455 kcal
Thus, we can conclude that energy required to produce 7.00 mol 
on the basis of given reaction is 455 kcal.
Answer:
See explanation below
Explanation:
In this case, we can use the Boyle's law. Assuming that the temperature of both trial remains constant, then:
P₁V₁ = P₂V₂ (1)
You should note that this expression is usable when you are dealing with gases. However, we can treat this unknown liquid as a gas, because all the air on the flask is removed, and we can assume that the liquid can behave like an ideal gas.
So using the above expression, we can solve for P₂:
P₂ = P₁V₁ / V₂ (2)
In this case, we already have the values of presures and volume, so replacing in this expression:
P₂ = 34.5 * 5 / 214
<h2>
P₂ = 0.806 kPa</h2>
This should be the pressure of the liquid.
Hope this helps
Answer:
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