Answer:
72.8 % (But verify explanation).
Explanation:
Hello,
In this case, with the following obtained results, the percent error is computed as follows:
Volume of vinegar= 7.0 mL
Volume of NaOH= (7+6.6+6.4)/3= 6.7 mL
Used concentration of NaOH= 1.5M
Concentration of acetic acid= (concentration of NaOH*volume of NaOH)/volume of vinegar= (6.7mL*1.5M)/7.0M= 1.44M
Assuming we have 100 mL (0.100L) of vinegar, moles of acetic acid in vinegar = 1.44M x 0.100 L= 0.144 mol
Mass of acetic acid in 100g of vinegar = 0.144 mol x 60.0g/mol= 8.64 g
% of acetic acid in vinegar=8.64 %
% error in percentage of acetic acid = [(8.64% - 5.0%)/5.0] x 100=72.8 %
Clearly, this result depend on your own measurements, anyway, you can change any value wherever you need it.
Regards.
Answer:
CH3COOH Ba OH 2 Ba CH3COO 2 H2O?
Explanation:
hope it helps you ~♥~
Answer: 0 neutrons
Explanation:
to find neutrons you subtract the atomic number from the Atomic mass. The atomic mass is 1. The atomic number is 1. So 1-1=0 making the neutrons in a hydrogen molecule 0.
Using the Avogadro's number (6.022*10^23)
9.11* (6.022*10^23)= 5.49*10^24 atoms of V
Answer:
Empirical Observation, Replicable Experiments, Provisional Results, Objective Approach, and Systematic Observation.
