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prisoha [69]
3 years ago
13

In step 2 of the experimental procedure, you added 6 M sodium hydroxide to the copper(II) nitrate solut form copper(II) hydroxid

e. You added a minimum amount of sodium hydroxide, but enough to complete reaction. How do you determine that enough sodium hydroxide has been added
Chemistry
1 answer:
kicyunya [14]3 years ago
4 0

Answer:

The solution becomes colorless and a light blue precipitate is formed.

Explanation:

When sodium hydroxide is added to copper(II) nitrate solution, a precipitate of  copper(II) hydroxide is formed.

The solution gradually becomes colorless as the light blue precipitate appears.

The reaction is complete (enough sodium hydroxide has been added) when the blue color of the solution completely disappears.

The equation of the reaction is;

Cu(NO3)2(aq) + 2NaOH(aq) → Cu(OH)2(s) + 2NaNO3(aq)

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A chemist combine did 3.50g of potassium level with chlorine gas to yield 6.6 7g of potassium for it. Assuming all the potassium
slega [8]

Answer: mass of chlorine reacted is 3.18 g

Explanation:

2 K + Cl2 = 2KCl

no. of moles of K = mass / molar mass

= 3.50 / 39

= 0.0897

no. of moles of KCl = mass / molar mass

= 6.67 / 74.5

= 0.0895  

no. of moles of Cl2 required = number of moles of KCl / 2

= 0.0895 / 2

= 0.0448 moles  

mass of Cl2 required = no. of moles of Cl2 required x molar mass

= 0.0448 x 71

= 3.1808 g ≈ 3.18 g

Therefore mass of chlorine reacted is 3.18 g

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3 years ago
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Concentration of Ba2+ is 1.00 mol/dm3 or 1M
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An atom has the following isotopes in the the following abundances. 20 10Z 30% , 19 10Z10% , 18 10Z 60% What is the average atom
Vera_Pavlovna [14]

The average atomic mass of the atom that has the following isotopes in the following abundances: 20 10Z 30% , 19 10Z10% , 18 10Z 60% is 18.7.

<h3>How to calculate average atomic mass?</h3>

The average atomic mass of an isotopic element is the weighted average of the atomic masses of the naturally occurring isotopes of an element.

According to this question, the atom has the following isotopes in the following abundances: 20 10Z [30%] = 30/100 × 20 = 6

19 10Z [10%] = 10/100 × 19 = 1.9

18 10Z [60%] = 60/100 × 18 = 10.8

The sum of these masses is the average atomic mass and is calculated as follows:

6 + 1.9 + 10.8 = 18.7

Therefore, the average atomic mass of the atom that has the following isotopes in the following abundances: 20 10Z 30% , 19 10Z10% , 18 10Z 60% is 18.7.

Learn more about average atomic mass at: brainly.com/question/13753702

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4 0
2 years ago
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LenKa [72]

Answer:

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