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hoa [83]
3 years ago
7

A science student observes that a dissolvable antacid tablet acts faster in relieving stomach pain when taken with warm water th

an when taken with water at room temperature. Based on the observation, suggest a potential problem that can be studied. Also, list the dependent, independent, and controlled variables that can exist in such an investigation.
Chemistry
2 answers:
goldfiish [28.3K]3 years ago
7 0

Answer:the medication would not last as long

Explanation:

Because of the desolving of the tablet so quickly it would

mojhsa [17]3 years ago
3 0

A potential problem that can be studied is "How does the temperature of injected water effect the effectiveness of medication tablets?" The dependent variable will be the medication tablet, and the independent will be the water temperature. The controlled variables will be the amount of medication, water, speed water is ingested, and diet of the person prior to ingesting the medication.

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How does the density of aluminum compare with the density of gold
rewona [7]
Gold has a very high density of about 19.32g/cm^3 while Aluminum has a low density of 2.7 gm/cm^3 which means gold can pack more amount of matter in a comparatively small space as compared to Aluminum.
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What are the types of connective tissue? Describe each type, and give an example of each.
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Answer:

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Explanation:

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Which of the following is a mixture?<br>steel<br>water<br>oxygen<br>gold​
Natasha_Volkova [10]

Water is the answer out of all the other options

6 0
3 years ago
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Explanation:

4 0
3 years ago
Read 2 more answers
A 1.450 g sample of an unknown organic compound , X, is dissolved in 15.0 g of toluene
muminat

Answer:

Molecular weight of the compound = 372.13 g/mol

Explanation:

Depression in freezing point is related with molality of the solution as:

\Delta T_f = K_f \times m

Where,

\Delta T_f = Depression in freezing point

K_f = Molal depression constant

m = Molality

\Delta T_f = K_f \times m

1.33 = 5.12 \times m

m = 0.26

Molality = \frac{Moles\ of\ solute}{Mass\ of\ solvent\ in\ kg}

Mass of solvent (toluene) = 15.0 g = 0.015 kg

0.26 = \frac{Mole\ of\ compound}{0.015}

Moles of compound = 0.015 × 0.26 = 0.00389 mol

Mol = \frac{Mass\ in\ g}{Molecular\ weight}

Mass of the compound = 1.450 g

Molecular\ weight = \frac{Mass\ in\ g}{Moles}

Molecular weight = \frac{1.450}{0.00389} = 372.13\ g/mol

4 0
3 years ago
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