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pantera1 [17]
3 years ago
15

When 25.0 grams of water are cooled from 20.0 degrees Celsius to 10.0 degrees Celsius the number of joules of heat energy releas

ed is?
Chemistry
2 answers:
vodka [1.7K]3 years ago
8 0

Heat energy released here

Q = mass x specific heat capacity of water x deltaT


= 25.0 x 4.184 x (-10.0)


= - 1046 Joules


1046 Joules of heat energy is released in this process.  




     

Nataliya [291]3 years ago
8 0

<u>Answer:</u> The amount of heat released is -1046 J

<u>Explanation:</u>

To calculate the amount of heat released, we use the equation:

q=mc\Delta T

where,

q = heat released = ?

m = mass of water = 25.0 g

c = specific heat capacity of water = 4.184 J/g.°C

\Delta T = change in temperature = T_2-T_1=(10.0-20.0)^oC=-10.0^oC

Putting values in above equation, we get:

q=25.0g\times 4.184J/g.^oC\times (-10.0^oC)\\\\q=-1046J

Hence, the amount of heat released is -1046 J

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