Answer:
£1837.5
Step-by-step explanation:
Given data
Cost of car P= £2100.
Rate r= 2.2%
Time t= 6 years
Now we want to find the worth after 6 years, let us apply the compound interest expression but this time for depreciation
A= P(1-r)^t
Substitute
A= 2100(1-0.022)^6
A= 2100*(0.978)^6
A= 2100*0.875
A= £1837.5
Hence the amount of the car after 6 years is £1837.5
Ok so add all of them together and you get 305 then divide it by how many numbers there are for the mean and you get 61 then add all of the diffrences from each number to the mean and we get 6 then 61 divided by 6 gets us 10.1 but round it to 10. hope this helped.
Gas mileage = 30.5 mi/gal
Volume of gas = 1.5 l
Note that 1 liter = 0.264172 gallons
Therefore
1.5 l = (1.5 l)*(0.264172 gal/l) = 0.3963 gal
Distance traveled is (Gas mileage, mi/gal)*(Gal of gas)
= (30.5)(0.3963) = 12.087 mi
Answer: 12 mi (nearest integer)
Answer:
Yes
Step-by-step explanation:
2 times 19=38
1 times 19=19
