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fiasKO [112]
3 years ago
11

Amy throws a softball through the air. What are the different forces acting on the ball while it’s in the air? The softball expe

riences force as a result of Amy’s throw. As the ball moves, it experiences from the air it passes through. It also experiences a downward pull because of . NextReset

Physics
2 answers:
scZoUnD [109]3 years ago
7 0
The force of the throw is an applied force

moving through the air is drag 

and the downward pull would be due to gravity
Komok [63]3 years ago
4 0

Answer:

As the ball moves, it experiences from the air it passes through. It also experiences a downward pull because of gravity

Explanation:

When Amy throws a ball in the air then initially the force is applied by Amy to accelerate the ball in the air.

Now after throwing into the air the ball will have forces as per the FBD

Ball will have a downward force which is due to gravity and its magnitude is always remains the same

Now ball also have another force opposite to the direction of motion due to air drag.

This air drag force depends on the speed of the ball and always opposite to the velocity of the ball.

so correct answer will be

As the ball moves, it experiences from the air it passes through. It also experiences a downward pull because of gravity.

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What is the value of work done on an object when a
tino4ka555 [31]
W = F * s
Here, F = 50 N
s = 15 m

Substitute their values, 
W = 50 * 15
W = 750 J

In short, Your Answer would be 750 Joules

Hope this helps!
7 0
3 years ago
A car traveling at 27.4 m/s hits a bridge abutment. A passenger in the car, who has a mass of 65.0 kg, moves forward a distance
Minchanka [31]

Answer:

F=43570.9N

Explanation:

We can calculate the acceleration experimented by the passenger using the formula v_f^2=v_i^2+2ad, taking the initial direction of movement as the positive direction and considering it comes to a rest:

a=\frac{v_f^2-v_i^2}{2d}=\frac{-v_i^2}{2d}

Then we use Newton's 2nd Law to calculate the force the passenger of mass m experimented to have this acceleration:

F=ma=\frac{-mv_i^2}{2d}

Which for our values is:

F=\frac{-(65kg)(27.4m/s)^2}{2(0.56m)}=43570.9N

6 0
4 years ago
A proton is released from rest at x=5 cm. what direction does it move?
Veronika [31]
Down to the left, down the the right, criss cross!
6 0
3 years ago
Which of your muscles push with the most force
noname [10]

Answer:

Wouldn't it be the muscles in your arms or legs since they have to push the most while they have gravity acting upon them?

Explanation:

3 0
3 years ago
What is the magnitude of the electric force of attraction between an iron nucleus (q=+26e) and its innermost electron if the dis
iris [78.8K]

Answer:

The magnitude of the force on an electron is 0.069 N.

Explanation:

Given that,

Distance between 1.70 A from the plutonium nucleus, d=1.5\times 10^{-12}\ m

The number of electron in iron nucleus is +26e.

To find,

The magnitude of the force between an iron nucleus.

Solution,

Total charge in the plutonium nucleus is, q=26\times 1.6\times 10^{-19}=4.16\times 10^{-18}\ C. The electric force between charges is given by :

F=\dfrac{kq^2}{d^2}

F=\dfrac{9\times 10^9\times (4.16\times 10^{-18})^2}{(1.5\times 10^{-12})^2}

F = 0.069 N

So, the magnitude of the force on an electron is 0.069 N. Hence, this is the required solution.

4 0
3 years ago
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