I'm not entirely sure but I believe that it will hit the ground and bounce back up
Answer:
F = 69.5 [N]
Explanation:
We must remember that the friction force is defined as the product of the normal force by the coefficient of friction, and it can be calculated by the following expression.

where:
N = normal force [N]
miu = friction coefficient
f = friction force = 22 [N]
Now we must calculate the force exerted by means of Newton's second law which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

where:
F = force exerted [N]
f = friction force [N]
m = mass = 95 [kg]
a = acceleration = 0.5 [m/s²]
Now replacing:
![F - 22 = 95*0.5\\F = 47.5 + 22\\F = 69.5 [N]](https://tex.z-dn.net/?f=F%20-%2022%20%3D%2095%2A0.5%5C%5CF%20%3D%2047.5%20%2B%2022%5C%5CF%20%3D%2069.5%20%5BN%5D)
Answer:
0.84 m
Explanation:
Given in the y direction:
Δy = 0.60 m
v₀ = 0 m/s
a = 9.8 m/s²
Find: t
Δy = v₀ t + ½ at²
0.60 m = (0 m/s) t + ½ (9.8 m/s²) t²
t = 0.35 s
Given in the x direction:
v₀ = 2.4 m/s
a = 0 m/s²
t = 0.35 s
Find: Δx
Δx = v₀ t + ½ at²
Δx = (2.4 m/s) (0.35 s) + ½ (0 m/s²) (0.35 s)²
Δx = 0.84 m
If it increased its speed steadily at a constant rate, then the average speed for the minute was
(1/2)(10m/s + 20m/s) = 15 m/s .
Rolling at an average speed of 15 m/s for 1 minute (60 seconds), it travels
(15 m/s) (60 sec) = 900 meters