Complete question is: While running, a person dissipates about 0.60 J of mechanical energy per step per kilogram of body mass. If a 60-kg person develops a power of 70 W during a race, how fast is the person running? (Assume a running step is 1.5 m long).
Answer: The person running at a speed of 2.91 m/s.
Explanation:
Given: Mass of runner = 60 kg
Runner dissipates = 0.6 J/kg per step
Average power = 70 W
1 step = 1.50 m
Energy dissipated by the runner is as follows.
Formula used to calculate the value of one step 'S' is as follows.
It is known that average velocity is equal to the total distance divided by time interval.
So, total distance for the given situation is as follows.
Hence, speed of the person is calculated as follows.
Thus, we can conclude that the person running at a speed of 2.91 m/s.
All the planets is the answer
Answer:
Explanation:
350 cm / 25 cm = 14 radians
14 rad / 2π rad/rev = 2.23 revolutions
Answer: 0.002 newtons
===================================================
Work Shown:
I'm assuming you meant to write "at 20 m/s^2" at the end. If so, then,
0.10 grams = 0.10/1000 = 0.0001 kg
m = 0.0001 kg = mass
a = 20 m/s^2 = acceleration
F = ma .... newton's second law
F = 0.0001*20
F = 0.002
The force required is 0.002 newtons