All categories

3 years ago

How do diagrams, sketches, or drawings help scientists understand concepts better?

2 answers:

7 0

They can have a visual which is usually always better to see instead of read or hear.They might use it to show something instead of writing.

Naddik [55]3 years ago

4 0

Answer:

They help scientists understand the concept better by helping them visualize how the process works in real life.

hope this helps

P.S:if you are struggling you got this and you can ask me for help anytime.

You might be interested in

URGENT!!!! Please respond in less than 5 mins hurry!!!!?!!?!!??!?

AleksAgata [21]

Answer:

1. A

2. B

Explanation:

1. Most of the answers don't make that much sense, so using process of elimination I resulted in this answer. I recommend you also try to check with others.

2. This question also was pretty confusing but when using process of elimination I resulted in either A or B. To me B makes more sense.

5 0

3 years ago

How many sulfur atoms are in 0.45 mol BaSO4??

Lemur [1.5K]

$(0.45 mol BaSO_{4})*(\frac{6.022*10^23 molecules}{mol})*(\frac{1 atom S}{1 molecule BaSO_{4}}) = 2.7*10^{23}$

4 0

3 years ago

Read 2 more answers

The sun is 150 kilometers from earth.if you wanted to explain to friend how far is what would you say

jasenka [17]

Answer:

150 times 1000 is how many meters it is away from earth because kilo means 1000

Explanation:

easy metric conversions

5 0

3 years ago

The reaction ch4 (g) + 2 o2 (g) ? co2 (g) + 2 h2o (g) is: the reaction ch4 (g) + 2 o2 (g) co2 (g) + 2 h2o (g) is: an exothermic

barxatty [35]

All of the above
_______________________________________________

5 0

4 years ago

What is the total volume of gaseous products formed when 116 liters of butane (C4H10) react completely according to the followin

Contact [7]

Answer: The total volume of the gaseous products is 1044.29 L

Explanation:

We are given:

Volume of butane = 116 L

At STP:

22.4 L of volume is occupied by 1 mole of a gas

So, 116 L of volume will be occupied by = $\frac{1}{22.4}\times 116=5.18mol$ of butane

The chemical equation for the combustion of butane follows:

$2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)$

For carbon dioxide:

By Stoichiometry of the reaction:

2 moles of butane produces 8 moles of carbon dioxide

So, 5.18 moles of butane will produce = $\frac{8}{2}\times 5.18=20.72mol$ of carbon dioxide

Volume of carbon dioxide at STP = (20.72 × 22.4) = 464.13 L

For water vapor:

By Stoichiometry of the reaction:

2 moles of butane produces 10 moles of water vapor

So, 5.18 moles of butane will produce = $\frac{10}{2}\times 5.18=25.9mol$ of water vapor

Volume of water vapor at STP = (25.9 × 22.4) = 580.16 L

Total volume of the gaseous products = [464.13 + 580.16] = 1044.29 L

Hence, the total volume of the gaseous products is 1044.29 L

3 0

3 years ago