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3 years ago

What is this process of producing more offspring than possibly survive called?

Chemistry

1 answer:

tamaranim1 [39]3 years ago

4 0

Darwin's Theory of Evolution by Natural Selection.

Darwin divided this theory into multiple parts but overall it fits into Darwin's Theory of Evolution by Natural Selection, so that would be your answer.

In case you're wondering about the others:

1. Organisms produce more offspring than actually survive.

2. Every organism must struggle to survive.

3. There is variation within a species.

4. Some variations allow members of a species to survive and reproduce better than others.

5. Organisms that survive and reproduce pass their traits to their offspring, and the helpful traits gradually appear in more and more of the population.

(these are brief explanations, they go into more detail)

Good luck!

You might be interested in

How much 0.02 m kmno4 solution should be needed if the solutions tested have a composition of 3% h2o2 by mass?

Nostrana [21]

When the concentration is expressed in mass percentage, that means there is 3 g of solvent H₂O₂ in 100 grams of the solution. Then, that means the remaining amount of solute is 97 g. We use the value of molarity (moles/liters) to determine the amount of solution in liters, denoted as V. The solution is as follows:

0.02 mol KMnO4/L solution * 158.034 g KMnO4/mol * V = 97 g KMnO4

Solving for V,
V = 30.69 L

6 0

3 years ago

A flashlight has a resistance of 2.4 . What voltage is applied by the batteries if the current in the circuit is

hammer [34]

Answer : The voltage applied by the batteries is, 6.0 V

Solution : Given,

Resistance of flashlight = 2.4 ohm

Current in the circuit = 2.5 Ampere

Formula used :

$V=IR$

where,

V = applied voltage

I = current in the circuit

R = resistance of light

Now put all the given values in the above formula, we get

$V=(2.5A)\times (2.4ohm)=6volt=6V$

Therefore, the voltage applied by the batteries is, 6.0 V

6 0

3 years ago

Read 2 more answers

Can someone help me with this problem.

ra1l [238]

Answer:

c. a small amount

Explanation:

Trace elements (or trace metals) are minerals present in living tissues in small amounts.

4 0

3 years ago

Learn how changes in binding free energy affect binding and the ratio of unbound and bound molecules.

Delvig [45]

C)[D]/[ED] = 5.20

D)[D]/[ED] = 5.20

E)[D']_T = 1.495* 10 ^-7 M

F)[D'] / [ED'] = 0.0579

Explanation:

E = 250 nM =2.5* 10 ^-7 mol/L , T=298.15 K

Dissociation constant of K_D = 1.3 μM (1.3 *10 ^-6 M)

E + D ⇄ ED → K_a = [ED] / [D][E] (association constant)

ED ⇄ E + D → K_D = [E][D] / [ED] (dissociation constant)

[E] =2.5*10^-7 mol/L

K_D = 1.3* 10^-6 M

K_D = [E][D] / [ED] → [D]/[ED] = K_D / [E]

= [D]/[ED] = 1.3* 10 ^-6 / 2.5 *10^-7

= 13/25 * 10

=130/25 = 5.20

[D]/[ED] = 5.20

ΔG =RTln Kd

ΔG_2 for E and D = 1.987 * 298.15 * ln 1.3*10^-6

ΔG_2 592.454 * [ln 1.3 +ln 10^-6]

ΔG_1 = 592.424 [0.2623 - 13.8155]

ΔG_2 = -592.424 * 13.553

ΔG_1 = -8184.633 cal/ mol

ΔG_1 = -8184.633 * 4.18 J/mol = -34244.508 J?mol

ΔG_1 = -34.245 KL/mol

so, ΔG_2 = ΔG_1 - 10.5 KJ/mol

ΔG_2 = -34.245 - 10.5

ΔG_2 = -44.745KJ / mol

ΔG_2 =RT ln K_D

-44.745 *10^3

=8.314 *298.15 lnK_D

lnK_D' = - 44745 / 2478.81 g

ln K_D' = -18.051

K_D' = -18.051

K_D' = e^-18.051

[D]/[ED] = 5.20

[E] = 2.5* 10 ^-7 mol/ L = a

K_D' = [E][D] / [ED'] E +D' → ED'

K_D' = a/2(x-(a/2) / (a/2)

KD' = x - a/2

=2.447 *10^-8 = (2.5/2) * 10^-7

x=2.447 * 10^-8 + 1.25 * 10^-7

x = 2.447 *10^-8 + 1.25 * 10 ^-7

x= 10^-7 [1.25 + 0.2447]

x = 1.4947 * 10^-7

[D']_T = 1.495* 10 ^-7 M

K_D' = [E][D'] / [ED']

[D'] / [ED'] = KD' / [E]

[D'] / [ED'] = 1.447 *10^-8 / 2.5* 10^-7

[D'] / [ED'] = 0.5788 * 10^-1

[D'] / [ED'] = 0.0579

5 0

3 years ago

At the end of seafloor spreading, where does the molten rock solidify?

olganol [36]

Answer:

As the two plates move apart from each other, which often occurs at a rate of several centimetres per year, molten rock wells up from the underlying mantle into the gap between the diverging plates and solidifies into new oceanic crust. Spreading centres are found at the crests of oceanic ridges.

Explanation:

I found this answer by taking notes in class

8 0

3 years ago