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DochEvi [55]
2 years ago
15

Please Help! Thank You

Chemistry
1 answer:
Ivanshal [37]2 years ago
3 0

Explanation:

the answer is true because I had this question and got it right

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What does ph measure? 6. msg behaves as a buffer. what is a buffer? 7. if we are interested in understanding how msg behaves as
Ket [755]

1. Answer;

- pH of a solution is the measures of molar concentration of hydrogen ions in a solution.

Explanation;

-pH is a measure of how acidic/basic  a substance is. The range goes from 0 - 14, with 7 being neutral. pHs of less than 7 indicate acidity, whereas a pH of greater than 7 indicates a base. pH is really a measure of the relative amount of free hydrogen and hydroxyl ions in a substance.

-The pH value states the relative quantity of hydrogen ions (H+) contained in a solution. The greater the concentration of H+ the more acidic the solution and the lower the pH.

2. Answer;

Buffer is a substance that minimizes change in concentrations of H+ and OH- in a solution.

Explanation;

-A buffer solution is an aqueous solution consisting of a mixture of a weak acid and its conjugate base, or vice versa.

-A buffer can resist pH change upon the addition of an acidic or basic components. It is able to neutralize small amounts of added acid or base, thus maintaining the pH of the solution relatively stable.

3. Answer;

By combining the two substances, we can analyze how the buffers react and stabilize the pH in the solution

Explanation;

- We found out that MSG was a buffer, and since it was a buffer more hydrogen ions is added to the solution. When we added it to the solution, it became a solid, which was what precipitated.

-There were a lot of Hydrogen protons floating around and with the MSG precipitate, we have all of these floating hydrogen and hydroxide ions. These hydrogens and hydroxide ions attach to the MSG, and the extra hydrogens would help to form the precipitate.


6 0
3 years ago
Which process is a chemical change? breaking of glass formation of frost magnetization of an iron nail loss of atmospheric ozone
Elenna [48]
The answer is "D" loss of atmospheric ozone
3 0
3 years ago
Read 2 more answers
I just need help on c-g. The whole question is there in case anyone needs it.
Elza [17]

Answer:

(c) 0.11; (d) -24.5 kJ·mol⁻¹; (e) See below; (f) Kc increases;

(g) No effect on ΔH

Step-by-step explanation:

(c) Kc at 125 °C  

In Part (a) one molecule of XY dissociated into one X and one Y.

       XY ⇌ X + Y

I:      10       0    0

C:     -1       +1   +1

E:      9        1     1

Kc = {[X][Y]}/[XY] = (1 × 1)/9 = ⅑ = 0.11

(d) ΔH

ΔH is a constant that is characteristic of the reaction.

ΔH = -24.5 kJ·mol⁻¹

(e) Effect of temperature on concentrations

If ΔH is negative, the reaction is exothermic.

Heat is a product of the reaction, so we can write the equation as

XY ⇌ X + Y + heat

If we lower the temperature, we are removing heat from the system.

<em>Le Châtelier's Principle</em> states that if you apply a stress to a system at equilibrium, it will respond by trying to relieve the stress.

We applied a stress by removing heat, so the system responds by producing more heat. The position of equilibrium moves to the right, and <em>more products will form</em>.

The diagram might look like the one below.

(f) Effect of temperature on Kc

Kc = [Products]/[Reactants]

We are increasing [Products] and decreasing [Reactants].

If you increase the numerator and decrease the denominator, you i<em>ncrease</em> the value of the quotient.

The value of the equilibrium constant increases when the temperature decreases.

(g) Effect of temperature on ΔH

Decreasing the temperature has no effect on ΔH, because the enthalpies of the reactants and products are properties of the substances themselves. They do not depend on the temperature.

7 0
3 years ago
Why should scientists preform experiments
svetoff [14.1K]

Answer:

To test the accuracy of a hypothesis or any findings that have already been made  

Explanation:

by performing experiments scientists get to test out any questions they have

4 0
3 years ago
Read 2 more answers
You wish to make a 0.289 M hydroiodic acid solution from a stock solution of 3.00 M hydroiodic acid. How much concentrated acid
nataly862011 [7]

Answer:

V_1=9.63mL

Explanation:

Hello,

In this case, we work on a dilution process in which we can state that the moles remain the same after the dilution process. In such a way, we can write:

n_1=n_2\\

That in terms of molarities and volumes is:

M_1V_1=M_2V_2

Whereas M_1 is the initial molarity (3.00 M) of the stock solution, M_2 the molarity of the diluted solution (0.289 M), V_1 the aliquot of the stock (concentrated) solution and V_2 the volume of the diluted solution (100 mL), thus, we compute V_1 as required:

V_1=\frac{M_2V_2}{M_1} =\frac{0.289M*100mL}{3.00M} \\\\V_1=9.63mL

Best regards.

7 0
3 years ago
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