To answer the problem we would be using this formula which isE = hc/L where E is the energy, h is Planck's constant, c is the speed of light and L is the wavelength
L = hc/E = 4.136×10−15 eV·s (2.998x10^8 m/s)/10^4 eV
= 1.240x10^-10 m
= 1.240x10^-1 nm
So, the recovery force of the spring is <u>2 N in the opposite direction of the pull</u>.
<h3>Introduction</h3>
Hi ! Here, I will help you about the spring recovery force. <u>The restoring force is the force that opposes the direction of the initial pull of the spring (either when the spring is pulled horizontally or vertically)</u>. The restoring force is strongly influenced by the type of spring (through the spring constant) and the length of the strain that occurs. Negative values in spring restoring force only indicate direction, not value. The equation that applies is as follows:
If the spring is pulled horizontally
With the following condition :
- F = recovery force (N)
- k = spring constant (N/m)
- = horizontal length change (m)
If the spring is pulled vertically
With the following condition :
- F = recovery force (N)
- k = spring constant (N/m)
- = vertical length change (m)
<h3>Problem Solving</h3>
We know that :
- Assume the spring is pulled horizontally
- k = spring constant = 4 N/m
- = horizontal length change = 0.5 m
What was asked :
- F = recovery force = ... N
Step by step :
<h3>Conclusion :</h3>
So, the recovery force of the spring is 2 N in the opposite direction of the pull.
The correct answer is: rock 1000 and bottle of soda 2000
Answer:
The minimum uncertainty in the velocity is 232.57 m/s.
Explanation:
Given that,
Location of a particle with uncertainty = 0.13 nm
Mass of particle
We need to calculate the minimum uncertainty in the velocity
Using heisenberg's uncertainty principle,
Put the value into the formula
Hence, The minimum uncertainty in the velocity is 232.57 m/s.