Answer:
18.7 m
Explanation:
= initial speed of the shot = 13 m/s
θ = angle of launch from the horizontal = 47 deg
Consider the motion along the vertical direction
= initial velocity along vertical direction = 13 Sin47 = 9.5 m/s
= acceleration along the vertical direction = - 9.8 m/s²
y = vertical displacement = - 1.80 m
t = time of travel
Using the kinematics equation

- 1.80 = (9.5) t + (0.5) (- 9.8) t²
t = 2.11 s
Consider the motion along the horizontal direction
x = horizontal displacement of the shot
= initial velocity along horizontal direction = 13 Cos47 = 8.87 m/s
= acceleration along the horizontal direction = 0 m/s²
t = time of travel = 2.11 s
Using the kinematics equation

x = (8.87) (2.11) + (0.5) (0) (2.11)²
x = 18.7 m